y-y1 = m (x-x1) y+3 = (1/4)(x+4) [using point (x1,y1)] or y–1 = (1/4)(x–12) [using point (x2,y2] [let's use this one since you did] To put this into Standard Form (Ax+By=C), y–1 = (1/4)(x–12) 4y - 4 = x - 12 -x + 4y - 4 = -12 [subtract x from both sides] -x + 4y = -8 [add 4 to both sides] x - 4y = 8 [multiply by (-1) to have x-coefficient positive
The answer to the question is B you do not have to sign if you use a pin
Answer:
x=1/5
Step-by-step explanation:
you can also use mathpapa it's a calculator that gives you the answer and solves it for you step by step.
Step-by-step explanation
Here ...I'm not too sure about the question as you have written
P = 2 ( 1 + 6 ) and ask to solve for L ...
.So I guess the question you have written is wrong .. ...and I guess there should be L in the place of 1.
...So let me correct the question....
P = 2 ( l + 6 )
P = 2l + 12
P - 2l = 12
- 2l = 12 - P
- 2l = - P + 12
Change the sign of both side of the equation...
2l = P + 12
divide both side by the same number...
L = ( P + 12 ) ÷ 2
Calculate the product of rational numbers...
Answer:
This will explain it
Step-by-step explanation:
To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
_____
The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
