Ask question

Ask question

All categories

Law Incorporation [45]

2 years ago

7

Marie has renters insurance that she must pay twice a year. If each payment is $96, how much money should she set aside each mon

th to cover
her renters insurance?
OA 548
OB. 516
OC $32
OD. $8

1 answer:

Vlad [161]2 years ago

4 0

Answer:

The answer is <u>B.) $16</u>

Step-by-step explanation:

Multiply 16$ by 6 which resembles half a year. You will get $96 from 16*6

You might be interested in

2x+y=3<br>x-y= 1<br><br>solve the equation

svetlana [45]

Answer:

x = 4/3

y = 1/3

Step-by-step explanation:

System of equations! This is set up really well to make the second equation equal x then substitute.

x - y = 1

x = 1 + y

and then our substitution:

2 (1+y) + y = 3

and solve:

2 + 2y + y = 3

3y + 2 = 3

3y = 1

y = 1/3

And now we can substitute that value into one of our equations:

x - (1/3) = 1

x = 4/3

Next we should check by substituting these values into both of our equations:

2 (4/3) + (1/3) = 3

9 / 3 does equal 3 !

(4/3) - (1/3) does equal 1 !

Therefore, x = 4/3 , and y = 1/3

4 0

3 years ago

Read 2 more answers

Darla bought 0.9 kilogram of red grapes and 0.35 kilogram of green grapes.

madam [21]

keep trying good luck to you

3 0

3 years ago

According to the National Bridge Inspection Standard (NBIS), public bridges over 20 feet in length must be inspected and rated e

slamgirl [31]

Answer:

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Step-by-step explanation:

For each bridge, there are only two possible outcomes. Either it has rating of 4 or below, or it does not. The probability of a bridge being rated 4 or below is independent from other bridges. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

For the year 2020, the engineers forecast that 9% of all major Denver bridges will have ratings of 4 or below.

This means that $p = 0.09$

Use the forecast to find the probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

Either less than 4 have a rating of 4 or below, or at least 4 does. The sum of the probabilities of these events is 1.

So

$P(X < 4) + P(X \geq 4) = 1$

We want $P(X \geq 4)$

So

$P(X \geq 4) = 1 - P(X < 4)$

In which

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.09)^{0}.(0.91)^{12} = 0.3225$

$P(X = 1) = C_{12,1}.(0.09)^{1}.(0.91)^{11} = 0.3827$

$P(X = 2) = C_{12,2}.(0.09)^{2}.(0.91)^{10} = 0.2082$

$P(X = 3) = C_{12,3}.(0.09)^{3}.(0.91)^{9} = 0.0686$

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3225 + 0.3827 + 0.2082 + 0.0686 = 0.982$

Finally

$P(X \geq 4) = 1 - P(X < 4) = 1 - 0.982 = 0.0180$

1.80% probability that in a random sample of 12 major Denver bridges, at least 4 will have an inspection rating of 4 or below in 2020.

6 0

3 years ago

In golf your scores can be under or over par. If a golfer has 3 games in which he scores 3 under on the first, 5 over in the sec

tiny-mole [99]

(-3)+(5)+(-3)=-1
The awnser is -1.

5 0

3 years ago

What equation can represent 3 increased by a numbwr x is 9

Ksivusya [100]

Answer:

fa

Step-by-step explanation:

4 0

3 years ago