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3 years ago

What is the answer to y=2/3x+4

Mathematics

1 answer:

In-s [12.5K]3 years ago

3 0

Answer:

y=2 over 3x-4

Step-by-step explanation:

I just know pog

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Given a function described as equation y =3x+4 ,what is y when x is 1,2,3

belka [17]

Answer:

When x =1, y = 3(1) + 4 = 7

When x = 2, y = 3(2) + 4 = 10

When x = 3, y = 3(3) + 4 = 13

5 0

3 years ago

If h(x) = x – 7 and g(x) = x2, which expression is equivalent to (g circle h) (5)?

Tema [17]

<h3>Answer: 4</h3>

=====================================================

Work Shown:

$(g \circ h)(x) = g(h(x))$

$g(x) = x^2\\\\g(h(x)) = (h(x))^2 \ \text{replace every x with h(x)}\\\\g(h(x)) = (x-7)^2 \ \text{replace h(x) with x-7}\\\\(g \circ h)(x) = (x-7)^2$

Now plug in x = 5

$(g \circ h)(x) = (x-7)^2 \\\\(g \circ h)(5) = (5-7)^2 \\\\(g \circ h)(5) = (-2)^2\\\\ (g \circ h)(5) = 4$

---------------------

Alternative approach:

h(x) = x-7

h(5) = 5-7

h(5) = -2

So this means

g(h(5)) = g(-2)

and

g(x) = x^2

g(-2) = (-2)^2

g(-2) = 4

Therefore making

$g(-2) = g(h(5)) = (g \circ h)(5) = 4$

8 0

4 years ago

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A square building with an area of 225 m2 has a garden surrounding it that has an equal width on all sides. The area of the garde

xenn [34]

Answer:

The width of the garden is 1.16 m

Step-by-step explanation:

step 1

<em>Find the area of the garden</em>

To find out the area of the garden multiply by 1/3 the area of the building

$225(\frac{1}{3})=75\ m^2$

step 2

Find the length side of the square building

The area of a square is

$A=b^2$

where

b is the length side of the square

we have

$A=225\ m^2$

$b^2=225\\b=15\ m$

step 3

Find the width of the garden

Let

x ----> the width of the garden

we know that

The area of the building plus the area of the garden is equal to

$(15+2x)^2=225+75$

solve for x

$225+60x+4x^2=225+75\\4x^2+60x-75=0$

Solve the quadratic equation by graphing

using a graphing tool

The solution is x=1.16 m

see the attached figure

therefore

The width of the garden is 1.16 m

Find the exact value

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$4x^2+60x-75=0$

$a=4\\b=60\\c=-75$

substitute in the formula

$x=\frac{-60\pm\sqrt{60^{2}-4(4)(-75)}} {2(4)}$

$x=\frac{-60\pm\sqrt{4,800}} {8}$

$x=\frac{-60\pm40\sqrt{3}} {8}$

$x=\frac{-60+40\sqrt{3}} {8}\ m$ ----> exact value

8 0

3 years ago

If angle ABC equals 130, what would the vertical angle equal to?

Mariulka [41]

Answer:

400

Step-by-step explanation:

400

7 0

3 years ago

Monty invested 8600 in a savings account with a yearly interest rate of 5% for 12 years how much simple interest did he earn

docker41 [41]

I=prt
I=8,600×0.05×12
I=5,160

4 0

3 years ago

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