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3 years ago

Find m∠U. Write your answer as an integer or as a decimal rounded to the nearest tenth.

Mathematics

1 answer:

galina1969 [7]3 years ago

6 0

Answer:

Answer:

50.2

Step-by-step explanation:

$ut = \sqrt{ {6}^{2} + {5}^{2} } \\ \sqrt{36 + 25} \\ \sqrt{61 } \\ using \: cosine \: rule \\ cos \: u = \frac{ {5}^{2} + 61 - 36 }{2 \times 5 \times \sqrt{61} } \\ \\ = \frac{25 + 61 - 36}{78} \\ \\ = \frac{50}{78 } \\ \cos \: u = 0.64 \\ m \:u = 50.2$

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Please help quickly

lions [1.4K]

Notice that 6 = 4+2,

11=6+5

19 = 11+8

30 = 19+11

Following the same pattern,

(next number) = 30 + 14 = 44

44 is the next number in the sequence 4, 6, 11, 19, 30, ...

4 0

3 years ago

four times a number decreased by 6 is less than -2 define a variable, write an inequality,and solve for the number?

choli [55]

4x - 6 > -2
4x > 4
x > 1
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3 0

4 years ago

Read 2 more answers

You are sitting on the ground flying a kite.

Neko [114]

Answer:

Height of the kite = 36 feet

Step-by-step explanation:

Triangle attached in the figure shows the complete picture,

I am sitting at point A, string connecting the kite and me is side AC, height of the kite from the ground is side BC and side AB representing the distance between me and the kite.

Length of side BC = h

Length of side AC = 39 feet

Length of side AB = 15 feet

By applying Pythagoras theorem in ΔABC,

AC² = AB² + BC²

(39)² = (15)² + h²

h² = 1521 - 225

h² = 1296

h = √1296

h = 36 feet

Therefore, kite is at 36 feet height.

5 0

3 years ago

Top Company holds 90 percent of Bottom Company’s common stock. In the current year, Top reports sales of $800,000 and cost of go

dsp73

Answer:

690,000

Step-by-step explanation:

given,

sale of the company = $800,000

cost of the good sold = $600,000

percentage = \dfrac{800000-600000}{800000}

= 25%

unrealized gross profit = $100000

= ( $100000× 0.40 ) × 0.25

= $ 10,000

consolidated Sales = 800000 + 300,000 - 100000

= $ 1,000,000

Consolidated COGS = $600,000 + $180,000 - 100,000 + 10,000

= 690,000

6 0

4 years ago

Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago