Answer:
Pr(the sum of the numbers rolled is either a multiple of 3 or an even number)=
Step-by-step explanation:
Let A be the event "sum of numbers is multiple of 3"
and B be the event "sum is an even number".
As our dice has six sides, so the sample space of two dices will be of 36 ordered pairs.
|sample space | = 36
Out of which 11 pairs have the sum multiple of 3 and 18 pairs having sum even.
So Pr(A)= 
and Pr(B)= 
and Pr(A∩B) = 
, as 5 pairs are common between A and B.
So now Pr(A or B)= Pr(A∪B)
= Pr(A)+Pr(B) - Pr(A∩B)
= + -
= 
=
Step-by-step explanation:
Here we can see it is a quadrilateral so
x + 108° + 65° + 53° = 360° ( being sum of angles of quadrilateral)
226° + x =360°
x = 360° - 226°
Therefore x = 134°
Answer:
mean is 5
Step-by-step explanation:
<h2>
MEAN</h2>
mean is regarded as the average number of items
<h3>mean formula:</h3>
<em>(sum of terms) / (number of terms)</em>
<h3><u /></h3><h3><u>Firstly</u></h3>
the numbers in the data set are :
3,3,3,4,6,6,7,8
they are already arranged in order, so no need to rearrange.
<h3><u>Next </u></h3>
add the numbers together to find the total :
3 +3 +3 +4 +6+ 6+7 +8
= 40
ALSO,
find how many number of terms they are --- this is 8
Last
use the mean formula to solve :
<em>(sum of terms) / (number of terms)</em>
= 40/8
= 5
<h3><em>
<u>the mean is the 5 </u></em></h3>
52.38 divided by 16 is <span>3.27</span>
Since we already know that the older child is a girl (a 100% chance to be a girl), there must be a 50% chance that the other child is a girl. Therefore, the probability that both children are girls is 50%.
Hope this helps!
