1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Phoenix [80]
2 years ago
8

Sammy watched

Mathematics
1 answer:
faltersainse [42]2 years ago
3 0

Answer:

5/12

Step-by-step explanation:

4 and 3 gcf is 12
8/12 - 3/12 = 5/12

You might be interested in
The discount price of a hat is $18. What is the regular price?
ASHA 777 [7]
20


Mark brainliest please
6 0
3 years ago
Given that ​f(x)=x^2 -19 and ​g(x)=17 -x, find ​(f-​g)(5​), if it exists.
pashok25 [27]

x^2 - 19 - (17 - x).

<em><u>Distribute -1 to each term of g(x).</u></em>

x^2 - 19 - 17 + x.

<em><u>Replace x with 5.</u></em>

5^2 - 18 - 17 + 5

25 - 18 - 17 + 4

<em><u>Simplify.</u></em>

-6 is your answer.


4 0
3 years ago
Calculate the unit prices for each of the items which is the better buy
Harman [31]
Calculate the unit prices for each of the items which is the better buy
8 0
3 years ago
Of the 45 animals on the farm, there are only pigs and chickens. The animals have a total of 124 legs. How many pigs and how man
Bess [88]

Answer:

on \: this \: farm \: there \: are \to \\  \underline{ \boxed{17 \: pigs }}\:  \\  and \\  \underline{ \boxed{28 \:chickens}}

Step-by-step explanation:

\\  \underline{ \boxed{solution \: to \: question \:  \boxed{ A}}} \\ \\ let \: the \: pigs \: be \to \: p \\ let \: the \: chicks \: be \to \: c \\let \: the \: total \: animals \: be \to \: 45 \\  hence \to \\ p + c = 45.......eq(1) \\ since \: chickens \: have \: two \: legs : \\  while \: pigs \: have \: four \: legs : \\ let \: animals \: with \: 2 \: legs \: be \to \: 2c \\ let \: animals \: with \: 4\: legs \: be \to \: 4p \\ the \: total \: number \: of \: animal \: legs  = 124 \\ hence \to \\ 4p + 2c = 124..........eq(2) \\ therefore \: the \: system \:  of \:  equations \: \\   to  \: describe  \: the  \: situation \: is \to \\ \\  p + c = 45 \\ 4p + 2c = 124 \\  \\  \\ \underline{ \boxed{solution \: to \: question \:  \boxed{B }}} \\  \\  \\ we \: could \: apply \: any \: of \: the \: simultanious \\  principles \to \\ here : am \: appling \: the \: elimination \: method   \to \\ p + c = 45 \\ 4p + 2c = 124  \\ to \: elimnate \: one \: varaible \: we \: multiply \: by \to \\ (4) \times p + c = 45 \\ (1) \times 4p + 2c = 124  \\ hence \to \\   - \frac{4p + 4c = 180}{4p + 2c = 124}  \\next \to \\   2c = 56 \\ c =  \frac{56}{2}  \\ \boxed{ c = 28} \\ lets \: work \: for \: p \to \\ p + c = 45 \\ p + 28 = 45 \\ p = 45 - 28 \\  \boxed{p = 17}

6 0
3 years ago
Carissa's Nursery buys plants for $10. She marks them up 20%. What is the selling price?
SashulF [63]

Answer:

$12

Step-by-step explanation:

The answer is 12 because 20% of 10 is 2 and 10 plus 2 is 12

3 0
3 years ago
Read 2 more answers
Other questions:
  • PLs help me with this it is really quick!!
    6·1 answer
  • The radius of the base of a cylinder is increasing at a rate of 7 millimeters per hour. The height of the cylinder is fixed at 1
    9·1 answer
  • You are a lab technician and it takes you 1 hour 30 minutes to complete a lab test. At this rate, how many hours would it take y
    9·1 answer
  • suppose that the weight,X, in pounds, of a 40 year old man is a normal random variable with mean 147 and standard deviation 16,
    9·1 answer
  • + → Co
    14·2 answers
  • How do you find the percent for this question<br> what is 25% off of 48 dollars
    15·2 answers
  • The scientist Robert Boyle was born in 1627. Work out an estimate for how many
    13·2 answers
  • Which probability is correct?<br> P(AB) = 1/2<br> P(BA) = 7/25<br> P(AC) = 6/23<br> P(CA) = 13/17
    11·2 answers
  • 1+1=<br> Easy question :&gt;
    8·2 answers
  • I am trying to simplify the following expression (7th grade math):<br><br> 94 - x - 67 - x
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!