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fiasKO [112]
3 years ago
8

1+1= Easy question :>

Mathematics
2 answers:
allochka39001 [22]3 years ago
5 0

Answer:

2

Very easy question :0

Veseljchak [2.6K]3 years ago
3 0

1+1= 2

Big brain >:3 Ty for the points tho ^^

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masha68 [24]
The correct answer is x = 43
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3 years ago
P= (x,y) is an arbitrary point on the circle x^2+y^2=36
sesenic [268]

Let (x,y) be an arbitrary point on the circle.

Then d = √[x-3)2 + (y-0)2] = √[x2 - 6x + 9 + y2]

Since x2 + y2 = 1, y2 = 1-x2.

So, d = √[x2 - 6x + 9 + 1 - x2]

     d = √(-6x+10)

Domain:  x is the x-coordinate of a point on the circle centered at (0,0) with radius 1.  So, -1≤x≤1.

             But, for d to be defined, we need -6x+10 ≥ 0.  So, x ≤ 5/3  (True for all x in [-1,1]).

             Domain = [-1,1]

Range:    -1 ≤ x ≤ 1   So, 6 ≥ -6x ≥ -6

                                    16 ≥ -6x+10 ≥ 4

                                     4 ≥ √(-6x+10) ≥ 2   That is, 2 ≤ d ≤4

              Range:  [2,4]

Step-by-step explanation:

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Please help! Anyone who knows about SSS, SAS, ASA, and AAS theorems.
umka21 [38]

Answer:

Step-by-step explanation:

Given:

∠C ≅ ∠E            

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2). ∠ABC ≅ ∠DBE                 2). Vertically opposite angles

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3 years ago
Three people of kaui Island are named Alice, Bob and Carol. At least one of them is a Knight and at least one is a Knave. Exactl
IrinaVladis [17]

Answer:  Alice has the prize

<u>Step-by-step explanation:</u>

\boxed{\begin{array}{c|c|c||l}\underline{Alice}&\underline{Bob}&\underline{Carol}&\underline{Prize}\\T&T&F&\text{Alice}\\T&F&F&\text{no possible answer}\\T&F&T&\text{no possible answer}\\F&T&T&\text{no possible answer}\\F&F&T&\text{no possible answer}\\F&T&F&\text{no possible answer}\end{array}}

Line 1:

Alice: Bob doesn’t have the prize (T) ... either Alice or Carol

Bob: I don’t have the prize (T) ... either Alice or Carol

Carol: I have the prize (F) ... either Alice or Bob

          Alice is true for all of them!

Line 2:

Alice: Bob doesn’t have the prize (T) ... either Alice or Carol

Bob: I don’t have the prize (F) ... Bob

Carol: I have the prize (F) ... either Alice or Bob

            <em>nobody satisfies all three statements.</em>

Line 3:

Alice: Bob doesn’t have the prize (T) ... either Alice or Carol

Bob: I don’t have the prize (F) ... Bob

Carol: I have the prize (T) ... Carol

            <em>nobody satisfies all three statements.</em>

Line 4:

Alice: Bob doesn’t have the prize (F) ... Bob

Bob: I don’t have the prize (T) ... either Alice or Carol

Carol: I have the prize (T) ... Carol

            <em>nobody satisfies all three statements.</em>

<em />

Line 5:

Alice: Bob doesn’t have the prize (F) ... Bob

Bob: I don’t have the prize (F) ... Bob

Carol: I have the prize (T) ... Carol

            <em>nobody satisfies all three statements.</em>

<em />

Line 6:

Alice: Bob doesn’t have the prize (F) ... Bob

Bob: I don’t have the prize (T) ... either Alice or Carol

Carol: I have the prize (F) ... either Alice or Bob

            <em>nobody satisfies all three statements.</em>

3 0
3 years ago
PICTURE IS SHOWN Help
Mrac [35]
Using complementary angles, <X is equal to <Z, so it's <Z = 35°.
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3 years ago
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