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2 years ago

8

1+1= Easy question :>

2 answers:

allochka39001 [22]2 years ago

5 0

Answer:

2

Very easy question :0

Veseljchak [2.6K]2 years ago

3 0

1+1= 2

Big brain >:3 Ty for the points tho ^^

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You sell your bicycle to your friend for 65$ your friend gives you x five dollar bills and y ten dollar bills. There are a total

jeka94

Answer:

There are $5$ five dollar bills and $4$ ten dollar bills.

Step-by-step explanation:

Given:

Selling price of bicycle $=\$65$ .

The friend gave $x$ five dollar bills and $y$ ten dollar bills.

Total number of bills $=9$ .

To find: Number of five dollar bills and ten dollar bills the friend gave.

Solution:

The friend gave $x$ five dollar bills and $y$ ten dollar bills and the friend gave $9$ bills in all.

So, $x+y=9$ .

$\Rightarrow x=9-y ...(i)$

Selling price of bicycle $=\$65$ .

So, $5x+10y=65...(ii)$

Putting the value of $x$ from equation $(i)$ in equation $(ii)$ .

$\Rightarrow 5(9-y)+10y=65$

$\Rightarrow 45-5y+10y=65$

$\Rightarrow 45+5y=65$

$\Rightarrow 5y=65-45$

$\Rightarrow 5y=20$

$\Rightarrow y=\frac{20}{5}$

$\Rightarrow y=4$

Now, putting the value of $y$ in equation $(i)$ .

$\Rightarrow x=9-4$

$\Rightarrow x=5$

Hence, there are $5$ five dollar bills and $4$ ten dollar bills.

5 0

3 years ago

HELP PLEASEE<br><br> Multiply negative 1 over 6 multiplied by negative 1 over 5

navik [9.2K]

Negative 1 over 11
negative 1 over 30
1 over 30
1 over 11
-1/6*-1/5 = 1/30

8 0

2 years ago

The the seats in the van are in pairs there are 16 seats How many pairs of seats are there

miskamm [114]

Eight, I am pretty sure. Eight times two is 16.

4 0

2 years ago

Read 2 more answers

Solve<br><img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D

Nostrana [21]

Answer:

$\displaystyle \begin{cases} \displaystyle {x} _{1} = - p \\ \displaystyle x _{2} = - q \end{cases}$

Step-by-step explanation:

we would like to solve the following equation for x:

$\displaystyle \frac{1}{p} + \frac{1}{q} + \frac{1}{x} = \frac{1}{p + q + x}$

to do so isolate $\frac{1}{x}$ to right hand side and change its sign which yields:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{1}{p + q + x} - \frac{1}{x}$

simplify Substraction:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{x - (q + p + x)}{x(p + q + x)}$

get rid of only x:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{ - (q + p )}{x(p + q + x)}$

simplify addition of the left hand side:

$\displaystyle \frac{q + p}{pq} = \frac{ - (q + p )}{x(p + q + x)}$

divide both sides by q+p Which yields:

$\displaystyle \frac{1}{pq} = \frac{ -1}{x(p + q + x)}$

cross multiplication:

$\displaystyle x(p + q + x) = - pq$

distribute:

$\displaystyle xp + xq + {x}^{2} = - pq$

isolate -pq to the left hand side and change its sign:

$\displaystyle xp + xq + {x}^{2} + pq = 0$

rearrange it to standard form:

$\displaystyle {x}^{2} + xp + xq + pq = 0$

now notice we end up with a <u>quadratic</u><u> equation</u> therefore to solve so we can consider <u>factoring</u><u> </u><u>method</u><u> </u><u> </u>to use so

factor out x:

$\displaystyle x( {x}^{} + p ) + xq + pq = 0$

factor out q:

$\displaystyle x( {x}^{} + p ) +q (x + p)= 0$

group:

$\displaystyle ( {x}^{} + p ) (x + q)= 0$

by <em>Zero</em><em> product</em><em> </em><em>property</em> we obtain:

$\displaystyle \begin{cases} \displaystyle {x}^{} + p = 0 \\ \displaystyle x + q= 0 \end{cases}$

cancel out p from the first equation and q from the second equation which yields:

$\displaystyle \begin{cases} \displaystyle {x}^{} = - p \\ \displaystyle x = - q \end{cases}$

and we are done!

3 0

2 years ago

A band has 36 members. They are arranged into 6 equal rows. How many band members are in each row? Can the same 36 members be pl

Galina-37 [17]

Answer:

6 people would be in each row // It isn't possible for there to be 7 equal rows

Step-by-step explanation:

36 members/6 rows= 6 people per row // 36 members/7 rows= 5.14..... people per row (just doesn't work!)

6 0

3 years ago