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2 years ago

How do I solve for AB? (rounded to the nearest tenth)

Mathematics

1 answer:

kolbaska11 [484]2 years ago

7 0

Answer:

The answer would be 8.1

Step-by-step explanation:

For the smaller triangle, you use the pythagorean theorem. a squared + b squared = c squared.

To find one of the legs, you do 5 squared - 3 squared = b squared.

25 - 9 = b squared. (BD)

16 = b squared

4 = b

Now for the bigger right triangle. You still use the same tactic.

7 squared + 4 squared = c squared (which is AB)

49 + 16 = c squared

65 = c squared

That means c would equal: square root of 65, which is 8.0622577483 which rounds to 8.1

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Answer:

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Step-by-step explanation:

To solve this, we are using the average rate of change formula:

$m=\frac{f(b)-f(a)}{b-a}$

where

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$b$ is the second point

$f(a)$ is the function evaluated at the first point

$f(b)$ is the function evaluated at the second point

We want to know the average rate of change of the function $f(x)=0.5^x-6$ form x = -3 to x = 0, so our first point is -3 and our second point is 0. In other words, $a=-3$ and $b=0$ .

Replacing values

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$m=\frac{0.5^0-6-(0.5^{-3}-6)}{0-(-3)}$

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$m=\frac{-5-2}{3}$

$m=\frac{-7}{3}$

$m=-\frac{7}{3}$

We can conclude that the average rate of change of the exponential equation form x = -3 to x = 0 is $-\frac{7}{3}$

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