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sergeinik [125]
2 years ago
10

What is the answer? A) 12 B)10 C)7 D)16

Mathematics
1 answer:
Alika [10]2 years ago
5 0

Answer:

g

Step-by-step explanation:

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hosting a dinner party for 38 people, you plan to serve peach pie for dessert. Each pie has 8 slices. how many pies must your bu
dem82 [27]

Answer:

4.75 or round up to 5.

Step-by-step explanation:

if each pie has 8 slices, then you must do 8+8+8... and so on until u reach 38. However you wont get exactly 38 because 8 doesn't add up evenly into 38. You can find the exact number by divding the amount of people, 38, by the number of slices per pie, 8. The answer will be 4.75 but you can not buy a fraction of a pie so you must round up to 5 whole pies. There will be extra left over in the end, but you cant round down because 4 pies would not be enough, so you must buy 5.

5 0
2 years ago
In a set of integers from 140 to 200 inclusive, how many integers are divisible by 4 and 6?
Ronch [10]

The answer to the question asked is 5.

The least common multiple of 4 and 6 is 12. In the range 140 to 200, there are

... floor(200/12) - ceiling(140/12) + 1 = 16 - 12 + 1 = 5

integers divisible by 12.

_____

The list of answer choices suggests that the question is intended to be, "how many integers are divisible by 4 or 6?"

The number divisible by 4 is

... floor(200/4) - ceiling(140/4) + 1 = 50 - 35 + 1 = 16

The number divisible by 6 is

... floor(200/6) - ceiling(140/6) + 1 = 33 - 24 + 1 = 10

We know from the above that there are 5 values that are divisible by both 4 and 6, so will be counted twice if we simply add the above numbers. Hence the number of values divisible by 4 or 6 is

... 16 + 10 - 5 = 21 . . . . . corresponds to selection C)

3 0
3 years ago
In ΔNOP, p = 38 cm, n = 13 cm and ∠O=152°. Find the area of ΔNOP, to the nearest square centimeter.
Vika [28.1K]

Answer:

Step-by-step explanation:

Answer-116

3 0
3 years ago
Which expression is equivalent to 2(a+b2)-a-2b?
ICE Princess25 [194]
3a-2b answer B, have a nice day bestie
6 0
3 years ago
Write in standard form 2+4i over 1+i
Levart [38]
So hmm a conjugate, is pretty much just, the same binomial, but with a different sign in the middle, so, a + b, has a conjugate of a - b
or -a + b, has a conjugate of - a  - b, or c - d, has a conjugate of c +d, and so on

anyway, the idea being, to "rationalize" the expression, namely, getting rid of the pesky radical in the denominator

so, we'll multiply the expression by 1, since anything times 1 is just itself

however, bear in mind, that 1, can be a/a, or b/b, or cheese/cheese, or anything/anything

so, we'll multiply the top and bottom of the fraction, by the conjugate of the denominator

anyhow, that said   \bf \cfrac{2+4i}{1+i}\cdot \cfrac{1-i}{1-i}\implies \cfrac{(2+4i)(1-i)}{(1+i)(1-i)}\implies \cfrac{2-2i+4i-4i^2}{1-i^2}\\\\
-----------------------------\\\\
\textit{recall that }i^2=-1\\\\
-----------------------------\\\\
 \cfrac{2-2i+4i-4(-1)}{1-(-1)}\implies \cfrac{2+2i+4}{2}\implies \cfrac{6+2i}{2}\implies \cfrac{6}{2}+\cfrac{2i}{2}
\\\\\\
\boxed{3+i}
7 0
3 years ago
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