What happens if your wifi is not working during home?

Mathematics

1 answer:

KIM [24]3 years ago

5 0

Answer:

Umm... Try turning it on and off? If that doesn't work, I don't know.

Step-by-step explanation:

You might be interested in

Someone please help me i don’t understand

frutty [35]

Answer:

Answer B

Step-by-step explanation:

Write out f(x) and g(x) in a column; we will subtract g(x) from f(x):

f(x) = x^2 - 9 or f(x) = x^2 - 9

-g(x) = -(2 - x) or -g(x) = +x -2

---------------------------------

f(x) - g(x) = x^2 + x - 11 (Answer B)

6 0

3 years ago

I’m not sure how to do this

seraphim [82]

$\bf \cfrac{\frac{x+4}{3}+\frac{1}{x}}{5+\frac{15}{x}}\qquad \cfrac{\impliedby \frac{LCD}{3x}}{\impliedby \stackrel{LCD}{x}}\implies \cfrac{\quad \frac{x(x+4)+3(1)}{3x}\quad }{\frac{x(5)+(1)15}{x}}\implies \cfrac{\quad \frac{x^2+4x+3}{3x}\quad }{\frac{5x+15}{x}}$

$\bf \cfrac{x^2+4x+3}{3\underline{x}}\cdot \cfrac{\underline{x}}{5x+15}\implies \cfrac{x^2+4x+3}{3(5x+15)}\implies \cfrac{x^2+4x+3}{15x+45}
\\\\\\
\cfrac{(x+3)(x+1)}{15x+45}\implies \cfrac{\underline{(x+3)}(x+1)}{15\underline{(x+3)}}\implies \cfrac{x+1}{15}$

7 0

3 years ago

I need help knowing how to show the work and how to get the answer and the answer it self

Morgarella [4.7K]

Find the separate areas.

We have a triangle with base 5 cm and height 5 cm, calculate the area:

$\sf A=\dfrac{1}{2}bh$

Plug in what we know:

$\sf A=\dfrac{1}{2}(5)(5)$

Multiply:

$\sf A=12.5~cm^2$

Now for the two quarter circles, we know that if we put these two together we will end up with a semi-circle with radius 5 cm. The formula for the area of a circle is:

$\sf A=\pi r^2$

A semi-circle is half of a whole circle, so the formula for the area of it must be:

$\sf A=\dfrac{1}{2}\pi r^2$

Now plug in what we know(use 3.14 to approximate for pi):

$\sf A\approx\dfrac{1}{2}(3.14)(5)^2$

Simplify the exponent:

$\sf A\approx\dfrac{1}{2}(3.14)(25)$

Multiply:

$\sf A\approx 39.25~cm^2$

Now add this to the area of the triangle to find the approximate area of the entire figure(round to the nearest tenth):

$\sf 39.25+12.5=\boxed{\sf 51.8~cm^2}$