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notsponge [240]
2 years ago
7

Three trigonometric functions for a given angle are shown below. Sine theta = Negative StartFraction 77 Over 85 EndFraction, cos

ine theta = StartFraction 36 Over 85 EndFraction, tangent theta = Negative StartFraction 77 Over 36 EndFraction What are the coordinates of point (x, y) on the terminal ray of angle mc020-2. Jpg, assuming that the values above were not simplified? (–77, –36) (–77, 36) (–36, 77) (36, –77).
Mathematics
2 answers:
Likurg_2 [28]2 years ago
8 0

Trigonometric functions are the ratio of the different sides of a right-angled triangle. We can say that the coordinates of the point are (-77, 36).

<h3>What are trigonometric functions?</h3>

Trigonometric functions are the ratio of the different sides of a right-angled triangle.

\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}

where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.

Given to us

Sin(\theta) = \dfrac{-77}{85}

Cos(\theta) = \dfrac{36}{85}

Tan(\theta) = \dfrac{-77}{36}

As we know that the Tangent(Tan) is the ratio of perpendicular and base. therefore, we can write the function as,

\rm Tan(\theta) = \dfrac{Perpendicular}{Base} = \dfrac{-77}{36}

therefore, the length of the perpendicular is 77, while the length of the base is 36.

As given to us that the value of sin is negative, therefore, the perpendicular will be on the negative side of the y-axis. While the value of cos is positive, therefore, the base will be on the positive side of the x-axis.

Thus, we can say that the coordinates of the point are (-77, 36).

Learn more about Trigonometric functions:

brainly.com/question/6904750

patriot [66]2 years ago
6 0

Answer:

d

Step-by-step explanation:

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tankabanditka [31]

Answer:

A.

x = \frac{7\sqrt{6}{3}

y = \frac{7\sqrt{6}}{3}

Step-by-step explanation:

Reference angle = 60°

Opposite = \frac{7\sqrt{2}}{2}

Hypotenuse = x

Adjacent = y

✔️To find x, apply the trigonometric function SOH:

Sin 60° = Opp/Hyp

sin 60° = \frac{\frac{7\sqrt{2}}{2}}{x}

\frac{\sqrt{3}}{2} = \frac{\frac{7\sqrt{2}}{2}}{x} (sin 60 = √3/2)

\frac{\sqrt{3}}{2} = \frac{7\sqrt{2}}{2}*\frac{1}{x}

\frac{\sqrt{3}}{2} = \frac{7\sqrt{2}}{2x}

Cross multiply

\sqrt{3}*2x = 7\sqrt{2}*2

2\sqrt{3}*x = 14\sqrt{2}

Divide both sides by 2

\sqrt{3}*x = 7\sqrt{2}

Divide both sides by √3

x = \frac{7\sqrt{2}}{\sqrt{3}}

Rationalize

x = \frac{7\sqrt{2}*\sqrt{3}}{\sqrt{3}*\sqrt{3}}

x = \frac{7\sqrt{6}{3}

✔️To find y, apply the trigonometric function TOA:

Tan 60° = Opp/Adjacent

Tan 60° = \frac{\frac{7\sqrt{2}}{2}}{y}

\sqrt{3} = \frac{\frac{7\sqrt{2}}{2}}{y} (tan 60 = √3)

\sqrt{3} = \frac{7\sqrt{2}}{2}*\frac{1}{y}

\sqrt{3} = \frac{7\sqrt{2}}{2y}

Cross multiply

\sqrt{3}*2y = 7\sqrt{2}

2\sqrt{3}*y = 7\sqrt{2}

Divide both sides by √3

y = \frac{7\sqrt{2}}{\sqrt{3}}

Rationalize

y = \frac{7\sqrt{2}*\sqrt{3}}{\sqrt{3}*\sqrt{3}}

y = \frac{7\sqrt{6}}{3}

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3 years ago
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Step-by-step explanation:

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