Another one I need help with!
2 answers:
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Answer:
A. 320
Step-by-step explanation:
See attachment for the figure
in order to determine Area of quadrilateral ABDF, we'll use the formula i.e
Area of quadrilateral ABDF = Area of AECD - Area of ΔBCD - Area of ΔDEF ->eq(1)
whereas, area of AECD = (AC × AE)
Area of ΔBCD = 1/2 (BC x CD)
Area of ΔDEF =1/2 ( EF x ED)
Substituting in eq(1)
eq(1)=>
Area of quadrilateral ABDF = (AC × AE) - 1/2 (BC x CD)- 1/2 ( EF x ED)
=(32 x 20) - 1/2(16 x 20) - 1/2(10 x 32)
= 640 - 160 - 160
= 640 - 320
= 320 square unit
Therefore, the area of quadrilateral ABDF is 320 square unit
Answer:
Therefore,
The three points for the line y = 0.5x - 7 ....( Red line )
point A( x₁ , y₁) ≡ ( 0 ,-7) (blue color point on the graph)
point B( x₂ , y₂) ≡ (14 , 0) (green color point on the graph)
point C(x₃ , y₃ ) ≡ (2 , -6) (purple color point on the graph)
The Graph is attached below..
Step-by-step explanation:
Given:
........... equation of a line
Let the points be point A, point B,and point C
To Find:
point A( x₁ , y₁) ≡ ?
point B( x₂ , y₂) ≡ ?
point C(x₃ , y₃ ) ≡ ?
Solution:
For Drawing a graph we require minimum two points but we will have here three points.
For point A( x₁ , y₁)
Put x = 0 in the given equation we get
y = 0.5 × 0 -7
y = -7
∴ point A( x₁ , y₁) ≡ ( 0 ,-7)
For point B( x₂ , y₂)
Put y= 0 in the given equation we get
0 = 0.5x -7
∴
∴ point B( x₂ , y₂) ≡ (14 , 0)
For point C(x₃ , y₃ )
Put x = 2 in the given equation we get
y = 0.5 × 2 - 7
y = -6
y = - 6
∴ point C(x₃ , y₃ )≡ (2 , -6)
Therefore,
The three points for the line y = 0.5x - 7 ....( Red line )
point A( x₁ , y₁) ≡ ( 0 ,-7) (blue color point on the graph)
point B( x₂ , y₂) ≡ (14 , 0) (green color point on the graph)
point C(x₃ , y₃ ) ≡ (2 , -6) (purple color point on the graph)
The Graph is attached below..
