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iogann1982 [59]
2 years ago
12

each table in the library can seat up to 7 people. There are enough tables for 175 in all. How many tables are in the library

Mathematics
1 answer:
RideAnS [48]2 years ago
4 0

Answer: <em>25 tables</em>

<em>This is a simple division problem</em>

<em>First let's take the given value of </em><em>175</em><em> people</em>

<em>Then we will take the value of </em><em>7</em><em> people per table in the library </em>

<em>Now we must divide </em><em>175</em><em> by </em><em>7</em><em> to get our answer </em>

<em />\frac{175}{7} =25

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I need help with this question
nikdorinn [45]
The area of each triangular face is
.. A = (1/2)*b*h
.. Aside = (1/2)*(6 cm)*(5 cm) = 15 cm^2

The area of the triangular base is
.. Abase = ((√3)/4)*s^2 = (√3)/4*(6 cm)^2 = 9√3 cm^2

The total surface area is the base area plus the area of the three sides.
.. Atotal = Abase + 3*Aside
.. = 9√3 cm^2 +3*15 cm^2
.. = (45 +9√3) cm^2
.. ≈ 60.6 cm^2


Actually, there's an error in the picture. The height of the side should be 4, and the length of the edge should be 5. Making that adjustment, the total area is 51.6 cm^2.

It is hard to tell what is intended. Not all answers are showing, so we can't "reverse-engineer" the problem from the answers.
7 0
3 years ago
Can anybody help me pleasee I don't understandd
o-na [289]
Hello there.

6(8 - 2y) = 4y

To solve for this, we need to apply the Distributive Property to the left side of the equation. This property allows us to multiply the number outside of the parenthesis by all numbers inside of the parenthesis.

6(8 - 2y)
6(8) + 6(-2y)
48 - 12y

Now, let’s take a look at our equation.

-12y + 48 = 4y

To make things more simple, we’ll add 12y to both sides of the equation. This will cancel out -12y on the left side of the equation and will turn 4y on the right side of the equation into 16y.

Our new equation is:

16y = 48

Now all we need to do is divide both sides by 16 to solve for y.

16y / 16 = y
48 / 16 = 3

Our final answer and solution is:

Y = 3

I hope this helps!
4 0
3 years ago
Please help ASAP IM IN DESPREATE NEED OF HELP
Advocard [28]

Answer:

See the attached image for the graph of the first system.

Step-by-step explanation:

Here's how to graph the first system.

Start with the inequality -y \le -2x-3.  You can make this easier to work with by multiplying through by -1.  Remember to switch the inequality sign when multiplying by a <u>negative</u> number.  OK, you get the inequality

y \ge 2x+3.

The graph will be a half-plane -- all the points on one side of a line.  The line that is the boundary of the half-plane has an equation:  y=2x+3 -- just use an  =  sign instead of the inequality sign.

Graph the line.

The equation of the line is in slope-intercept form:  y = mx + b, so you can tell the y-intercept is 3 and the slope is 2 (think of it as a fraction 2/1).  Graph the line by going to the point (0, 3) -- the y-intercept -- then use the slope 2/1 interpreted as "rise over run" to go up 2 units and right 1 unit, arriving at the point (1, 5).  Draw the line through those points, (0, 3) and (1, 5).

Now you have to decide which side of the line the inequality y \ge 2x+3 is describing. To do this, pick a point which is not on the line, plug its coordinates into the inequality; if the result is true, shade the side of the line the point you picked is on (if false, shade the <u>other</u> side!)

An easy point to pick in this case is the origin, (0, 0).  Put zeros in for x and y in the inequality, and you'll get the statement 0 \ge 2(0)+3 \, \Rightarrow \, 0 \ge 3.  That's <u>false</u>, so shade the side of the line <u>not</u> containing the origin.  In the image below, the shading is in purple.

All right, now for the other inequality, x+2\le 0.  Subtract 2 from both sides and the inequality becomes x \le -2.  This, too, graphs as a half-plane whose boundary line has equation x=-2.  Graph the line.  A line with an equation that has  x  in it but not  y is a vertical line with all its x-coordinates equal to the number on the right side of the equation.  This line is vertical and goes through points such as (-2, 0).

Pick a point <u>not</u> on the line (the origin works again).  Put the coordinates into the inequality to get 0\le -2 which is <u>false</u>.  Shade the side of the vertical line which does <u>not</u> contain the origin.  In the image below, the shading is in black.

Finally,  YAY!  \o/ ,  the solutions to the system are all the points in the plane that got shaded twice.  In the image, they are the cross-hatched points above the purple line and to left of the black line.

Note: If you get a system with three inequalities, you'll be graphing three half-planes and looking for points that got shaded three times!

Note: One of your questions has the inequalities x \ge 0 and y \ge 0 in it.  These two inequalities say that the x and y coordinates are both positive or zero, confining your attention to Quadrant I in the upper-right part of a graph, above the x-axis <u>and</u> to the right of the y-axis.

7 0
3 years ago
What is the range of the function below in set builder notation? y=|x-3|
Kisachek [45]

Answer:  \{y | \ y \in \mathbb{R}, \ y \ge 0\}

This translates to "y is any real number such that it is 0 or larger".

The reasoning is that the result of any absolute value function is either 0 or positive. In other words, we'll never get a negative result of an absolute value function. This is due to how absolute value represents distance. Negative distance does not make sense.

So if y = |x-3| then y = 0 is the smallest output possible. We could have any positive output we want.

In terms of a graph (see below), the V shape is at the lowest point (3,0). The y coordinate is all we care about in terms of finding the range. So we see the lowest y value is y = 0.

4 0
3 years ago
What is 1/6 divided by 1/2
Blababa [14]

Answer:

The answer is 3

Step-by-step explanation:

I put the answer simplified if needed.

8 0
2 years ago
Read 2 more answers
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