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Ksivusya [100]
3 years ago
9

Prove that 3n< n! if n is an integer greater than 6.

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
4 0
Let n=7. Then

3(7)=21

Assume the inequality holds for n=k, so that 3k. Then for n=k+1, you have, for k>7,

3(k+1)

so the statement is true.
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Anyone know the answer good 15 points ???
Klio2033 [76]

Answer:

When solving for a variable, you undo all operations done to that variable.

In the equation 6x - 3 = -51 we see on the left-hand side that the variable x is being multiplied by 6 and subtracted 3 times.

We can reverse the subtraction operation by using the inverse of subtraction.

Which is the addition operation. If we add 3 to the left-hand side, the -3 term will disappear.

But wait! Anything we do on one side we must do also on the opposite side.

6x - 3 + 3 = -51 + 3

6x             = -48

Now how can we undo the multiplication operation done to x?

We can use division. It will make the 6 coefficient disappear!

6x / 6 = -48/6

x = -8

<h3>So, x is equal to -8. (C) </h3>

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2 years ago
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Klio2033 [76]

Answer:

Step-by-step explanation:

2 times a number, 2y

the sum of that and 9, 2y+9 ‘is’ 7

2y+9=7

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lorasvet [3.4K]
313. Anything .5 or higher rounds up to the higher number.
Hope it helps!
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