Let point A(0,-2)
and B(2,-5)
slop of line equals to
(2-0)/(-5-(-2))=2/-3=-2/3
y=mx+c
y=-2/3x+c
Verify piont A
-2=-2/3×0+c
c=-2
Final equation of line is
y=-2/3x-2
2x+3y+6=0
Now choose any random point it positive
2x+3y+6>0
Answer:
existing
Step-by-step explanation:
Graph B has y-intercept at 2
Answer:
180°
Step-by-step explanation:
9514 1404 393
Answer:
both are (-∞, ∞)
Step-by-step explanation:
The domain and range of any odd-degree polynomial are both "all real numbers." They go from -infinity to +infinity.
Your polynomial is of degree 3, so is of odd degree. The arrows on the ends of the curve indicate it extends to infinity in that direction.
y → +∞ for x → +∞
y → -∞ for x → -∞
