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otez555 [7]
3 years ago
14

The long division below shows the first term of the quotient. Which polynomial should be subtracted from the dividend first? mc0

03-1.jpg

Mathematics
2 answers:
nasty-shy [4]3 years ago
6 0
X³+2x² is your answer i got it right in my test ;)
Thepotemich [5.8K]3 years ago
5 0

Answer: x^3 + 2x^2

Explanation:

when we divide polynomial x^3 +3x^2 +x  by  x+2

we will first consider polynomial  with  one degree less than the numerator that will  be x^{2} and as when we multiply x^{2} by x+2 by the rule of long division we get x^3 +2x^2

Hence, x^3 +2x^2  will be the first term we will divide from the dividend.


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Simplify: [(6x^3 y^-4)^-2] / [(3x^2 y^5)^-3] (The / is the fraction line)
Vera_Pavlovna [14]

\bf \cfrac{(6x^3y^{-4})^{-2}}{(3x^2y^5)^{-3}}\implies \stackrel{\textit{using positive exponents}}{\cfrac{(3x^2y^5)^3}{(6x^3y^{-4})^2}}\implies \stackrel{\textit{distributing the exponent}}{\cfrac{(3^3x^{2\cdot 3}y^{5\cdot 3})}{(6^2x^{3\cdot 2}y^{-4\cdot 2})}} \\\\\\ \cfrac{27x^6y^{15}}{36x^6y^{-8}}\implies \cfrac{27}{36}\cdot \cfrac{x^6y^{15}}{x^6y^{-8}}\implies \cfrac{3}{4}\cdot x^6x^{-6}y^{15}y^8\implies \cfrac{3}{4}\cdot x^{6-6}y^{15+8} \\\\\\ \cfrac{3}{4}\cdot 1y^{23}\implies \cfrac{3y^{23}}{4}

6 0
3 years ago
Read 2 more answers
Hello! If someone could help me answer this it would be appreciated! <3
Leona [35]

Answers:

  • In the top row, the first and third polygons are regular polygons.
  • In the bottom row, only the first polygon is a regular polygon

============================================================

Explanation:

A regular polygon must have all sides of equal length. Also, all angles must be the same measure. This applies to the equilateral triangle in the upper left corner, and the square in the upper right corner. Each angle of the square is 90 degrees even though your teacher didn't use right angle markers.

The middle figure in the top row is not a regular polygon because the sides are not all the same length. Also, the angles are different.

--------------------

In the bottom row, only the first figure is a regular polygon for similar reasons mentioned earlier. The second figure is not a regular polygon because this figure is concave. Only convex polygons can be regular.

The third figure in the bottom row is not regular because one side is longer than the others.

3 0
2 years ago
What is tan B?<br> А<br> 34<br> 16<br> В<br> 30<br> с<br> 15
Thepotemich [5.8K]

Answer:

8/15

Step-by-step explanation:

With reference angle B

Perpendicular (p) = 16

base (b) = 30

so

Tan B = p/ b

= 16/30

= 8/15

Hope it will help :)❤

7 0
3 years ago
Graph f(x)=2ˣ−1 and g(x)=−x+5 on the same coordinate plane.
Evgesh-ka [11]

Graph attached

  • Solution is (2,3)

3 0
2 years ago
NEED HELP ASAP!!!!!!!!!!!<br><br> 2. Solve for x<br> 3. Solve for x
Anton [14]

Answer:

2. x = 47

3. x = 2

Step-by-step explanation:

These problems involve proportions, or equivalent ratios.  You can solve for 'x' in each by using cross-multiplication and division.

2.  28(7) = 4(x + 2)

Distribute = 196 = 4x + 8

Subtract 8 from both sides: 196 - 8 = 4x + 8 - 8 or 188 = 4x

Solve for x:  x = 47

3.  2(2x + 7) = 11(3x - 4)

Distribute: 4x + 14 = 33x - 44

Add 44 to both sides: 4x + 14 + 44 = 33x - 44 + 44 or 4x + 58 = 33x

Subtract 4x from both sides: 4x + 58 - 4x = 33x - 4x or 58 = 29x

Solve for x: x = 2

4 0
3 years ago
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