Question

Condense into a single logarithm and simplify:id="TexFormula1" title="2\log _(10)x+\log _(10)5" alt="2\log _(10)x+\log _(10)5" align="absmiddle" class="latex-formula">

Answer 1

Answer:

$2\, \log_{10}(x) + \log_{10}(5) = \log_{10}(5\, x^{2})$.

Step-by-step explanation:

For any given base $b > 0$, $x > 0$, and $y > 0$:

$\log_{b}(x) + \log_{b}(y) = \log_{b}(x\, y)$.

For all real $y$ (including both $y > 0$ and $y \le 0$,) as long as $b > 0$, $x > 0$:

$y\, \log_{b}(x) = \log_{b}(x^{y})$.

Apply the second rule to rewrite $2\, \log_{10}(x)$:

$\begin{aligned}2\, \log_{10}(x) &= \log_{10}(x^{2})\end{aligned}$.

Apply the first rule:

$\begin{aligned}\log_{10}(x^{2}) + \log_{10}(5) = \log_{10}(5\, x^{2})\end{aligned}$.

Overall:

$\begin{aligned}& 2\, \log_{10}(x) + \log_{10}(5)\\ =\; & \log_{10}(x^{2}) + \log_{10}(5) \\ =\; & \log_{10}(5\, x^{2})\end{aligned}$.