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sdas [7]
3 years ago
15

A point undergoes two transformations. The x-coordinate's sign changes and the y-coordinate increases. What were the transformat

ions?
The point was reflected over the y-axis and translated down.
The point was reflected over the x-axis and translated to the right.
The point was reflected over the y-axis and translated up.
The point was reflected over the x-axis and translated to the left.
Mathematics
2 answers:
aniked [119]3 years ago
6 0
For this case we are going to define the original coordinates:
 (x, y): original coordinates.
 We apply the transformation:
 (x, y) -------> (-x, y + k)
 We have:
 -x: reflection on the y axis.
 y + k: translation k units up.
 Answer:
 
The point was reflected over the y-axis and translated up.
NikAS [45]3 years ago
5 0

Answer:  The point was reflected over the y-axis and translated up.

Step-by-step explanation:

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21r-7-r+5=-52 solve for r
malfutka [58]

Answer:

r = - 2.5

r=-2\frac{1}{2}

Step-by-step explanation:

21r - 7 - r + 5 = - 52

20r - 2 = - 52

20r - 2 + 2 = - 52 + 2

20r = - 50

20r ÷ 20 = - 50 ÷ 20

r = - 2.5

3 0
3 years ago
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Plz help me I don’t understand this
Firlakuza [10]

The answer should be 31/10

3 0
3 years ago
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If a bus travels to a town 29 miles away, how long will it take to get there going 45 mph?
m_a_m_a [10]
S=d/t
45=29/t
t=45/29
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5 0
3 years ago
Elise and her dad are planning to attend the state fair. An adult ticket is $21.00. The price of an adult ticket is $10.00 more
belka [17]

Answer:

C)two thirds x + 10 = 21

Step-by-step explanation:

The equation for determining how much it would be paid for the student tickets is shown below:

Given that

The ticket of an adult is $21

Now let us assume the price of the student ticket be x

So two third would be 2 ÷ 3x

And for adult it would be

2 ÷ 3x + 10

Now the equation is

2 ÷ 3x + 10 = 21

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6 0
3 years ago
Use summation notation to write the series 49 + 54 + 59 +... for 14 terms.
My name is Ann [436]

Answer:

Arithmetic sequence states that a sequence of numbers such that the difference between the consecutive terms is constant.

it is given by:  a_n = a+(n-1)d where a is the first term , n is the number of term and d is the common difference.

Given the series: 49 + 54 + 59+ ......

here, Common difference(d) = 5

First term(a) = 49

by definition we have;

For nth term

a_n = a+(n-1)d

a_n = 49+(n-1)5

a_n =49+5n -5 = 5n + 44

To write the series using summation notation for 14 terms

Summation symbol '\sum'

The series for 14th terms is given by;

\sum_{n=1}^{14}(5n +44)


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3 years ago
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