Question

Show the equation in slope-intercept form that represents a line that has a slope of 1/3 and passes through (12, -6)?

Answer 1

Hi!

I can help you with joy!

First of all, we are given the slope and a point that the line passes through.

So, we can write the line's equation in Point-Slope Form:

$\text{y-y1=m(x-x1)}$

Plug in the values:

$\text{y-(-6)=m(x-12)}$

$\tt{y+6=\frac{1}{3} (x-12)}$

$\tt{y+6=\frac{1}{3} x-4$

Move 6 to the right:

$\tt{y=\frac{1}{3} x-4-6}\\\tt{y=\frac{1}{3} x-10$

Hope it helps!

Ask me if you have any doubts.

• Enjoy Your Day/Night!

~Silent~

Answer 2

Answer:

y = 1/3x - 10

Step-by-step explanation:

→ Write gradient in form y = mx + c

y = 1/3x + c

→ Substitute in 12 and -6

-6 = 4 + c

→ Solve for c

c = -10

→ Rewrite into y = mx + c format

y = 1/3x - 10