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eimsori [14]
3 years ago
6

Show the equation in slope-intercept form that represents a line that has a slope of 1/3 and passes through (12, -6)?

Mathematics
2 answers:
Nutka1998 [239]3 years ago
6 0

Hi!

I can help you with joy!

First of all, we are given the slope and a point that the line passes through.

So, we can write the line's equation in Point-Slope Form:

\text{y-y1=m(x-x1)}

Plug in the values:

\text{y-(-6)=m(x-12)}

\tt{y+6=\frac{1}{3} (x-12)}

\tt{y+6=\frac{1}{3} x-4

Move 6 to the right:

\tt{y=\frac{1}{3} x-4-6}\\\tt{y=\frac{1}{3} x-10

Hope it helps!

Ask me if you have any doubts.

  • Enjoy Your Day/Night!

~Silent~

alukav5142 [94]3 years ago
3 0

Answer:

y = 1/3x - 10

Step-by-step explanation:

→ Write gradient in form y = mx + c

y = 1/3x + c

→ Substitute in 12 and -6

-6 = 4 + c

→ Solve for c

c = -10

→ Rewrite into y = mx + c format

y = 1/3x - 10

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