Humood's house is (-5,7)
1 answer:
The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer:
The options to complete the proof are placed in the boxes of the attached drawing created with Microsoft Word
Step-by-step explanation:
Please see attached drawing of the proof created with Microsoft Word
The two column proof can be presented as follows;
Statement Reason
Given
m∠3 + m∠4 = 180° Linear pair postulate
∠1 ≅ ∠3 Corresponding Angle Theorem
m∠1 + m∠4 = 180° Transitive Property
m∠1 and m∠4 are supplementary Definition of supplementary angles
