Question

Humood's house is (-5,7)

Answer 1

The distance from Humood's house to the school is 500m

How to determine the distance from Humood's house to the school?

The given parameters are:

Humood's house is (-5,7)

The school is (3,1)

The distance between both points is calculated using

$d = \sqrt{(x_2- x_1)^2 + (y_2 - y_1)^2$

Substitute the known values in the above equation

$d = \sqrt{(-5 - 3)^2 + (7 - 1)^2$

Evaluate

d = 10

Each unit in the graph is 50m.

So, we have

Distance =10 * 50m

Evaluate the product

Distance = 500m

Hence, the distance from Humood's house to the school is 500m

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