Humood's house is (-5,7)
1 answer:
The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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9514 1404 393
Answer:
- x = 19
- x = 34
- x = 39
Step-by-step explanation:
1. A right angle has a measure of 90°. The whole is the sum of the parts.
(2x +3)° +49° = 90°
2x +52 = 90 . . . . . . . . divide by °, collect terms
2x = 38 . . . . . . . . . . . . subtract 52
x = 19 . . . . . . . . divide by 2
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2. A linear pair measures 180°. The whole is the sum of the parts.
(x -5)° +151° = 180°
x +146 = 180 . . . . . . . divide by °, collect terms
x = 34 . . . . . . . . .subtract 146
__
3. We presume this pair of angles is supposed to be supplementary. That is, their sum is 180°.
64° +(3x -1)° = 180°
3x +63 = 180 . . . . . . . divide by °, collect terms
3x = 117 . . . . . . . . subtract 63
x = 39 . . . . . divide by 3
Answer:
= 9
Step-by-step explanation:
Given that,
Asn expression :
We need to evaluate the above expression.
We know that,
So,
or
So, the value of is 9. Hence, the correct option is (b).