Humood's house is (-5,7)
1 answer:
The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer:
The answer is below
Step-by-step explanation:
Solve this system of equations by graphing. First graph the equations, and then type the solution. y=2x+2 y=x–2
Solution:
The equation of a straight line is in the form y = mx + b, where m is the slope of the graph and b is the y intercept (value of y when x = 0). To graph the line, online geogebra graphing calculator was used for plotting the two graphs by writing the equation of the graphs.
After plotting the two graphs, the intersection of the two lines should be traced to get the x coordinate and y coordinate of the point. This point is the solution of the two graph equations, hence:
The solution = (-4, -6)
