Answer:
I believe the answer would be A!
Step-by-step explanation:
If you need $10 total, then charging $1 for 4 apples would get you $4, and charging $1.50 for 4 oranges would get you $6, totaling $10!
I’m going to assume you know slope-intercept form. The work will be displayed below on my magnificent, college-ruled paper.
Answer:
Wanda and Dave will catch each other in 54 seconds after Dave starts walking.
Step-by-step explanation:
Let Wanda and Dave catch each other when x be the time after Dave starts walking and y be the distance covered by them
It is given that Wanda started walking along a path 27 seconds before Dave and the constant speed of Wanda is 3 feet per second.



.... (1)
The constant speed of Dave is 4.5 feet per second.

.... (2)
Equate equation (1) and (2).


Divide both sides by 1.5.


Therefore, Wanda and Dave will catch each other in 54 seconds after Dave starts walking.
Answer:
Its B
Step-by-step explanation:
Try and read throught it slowly and everytime you hit a variable go down the the answer and find where it is. That helped me a lot
Part A. You have the correct first and second derivative.
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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.
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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out
To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0.
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well.