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wel
3 years ago
7

The sum of Kyra's and Caleb's ages is 37. Caleb's age is equal to twice the quantity of Kyra's age decreased by 4. Let k represe

nt Kyra's age.
Complete each expression to represent the situation.



Kyra's age: , 1 of 3.
Select Choice
years



Caleb's age: , 2 of 3.
Select Choice
(k − , 3 of 3.
Select Choice
) years

Part B
Add the two expressions and set this sum equal to 37 to model the situation with an equation. Solve for k. How old is Kyra?
Mathematics
1 answer:
frosja888 [35]3 years ago
7 0
Based on the given conditions, formulate:
Rearrange unknown terms to the left side of the equation:
Combine like terms:
Calculate the sum or difference:
Divide both sides of the equation by the coefficient of variable:
Answer: k=41/3
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Answer:

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Step-by-step explanation:

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Answer:

\sqrt{8x^7y^8= 2x^3y^4 * \sqrt{2x}

Step-by-step explanation:

Given

\sqrt{8x^7y^8

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\sqrt{8x^7y^8

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\sqrt{8*x^7*y^8

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\sqrt{4 * 2 *x^6 * x*y^8

Split each factor

\sqrt{4} * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}

Evaluate \sqrt4

2 * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}

Apply law of indices:

2 * \sqrt{2} * x^{6*\frac{1}{2}} * \sqrt{x} * y^{8*\frac{1}{2}}

2 * \sqrt{2} * x^3 * \sqrt{x} * y^4

Reorder

2* x^3 * y^4 * \sqrt{2}  * \sqrt{x}

2x^3y^4 * \sqrt{2}  * \sqrt{x}

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Hence:

\sqrt{8x^7y^8= 2x^3y^4 * \sqrt{2x}

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3 years ago
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MATH WORD PROBLEM
Sloan [31]

cost of one regular admission ticket = $ 10

cost of one senior citizen ticket = $ 5

<h3><u>Solution:</u></h3>

Let "r" be the cost of one regular admission ticket

Let "s" be the cost of one senior citizen ticket

Given that,

<em><u>On day 1 you sold 30 Regular Admission tickets and  20 Senior Citizen tickets for a total of $400</u></em>

So we can frame a equation as:

30 Regular Admission tickets x cost of one regular admission ticket + 20 Senior Citizen tickets x cost of one senior citizen ticket = $ 400

30 \times r + 20 \times s = 400

30r + 20s = 400 ----- eqn 1

<em><u>Day two you sell 40 Regular Admission tickets and only 10 Senior  Citizen tickets for a total of $450</u></em>

So we can frame a equation as:

40 Regular Admission tickets x cost of one regular admission ticket + 10 Senior Citizen tickets x cost of one senior citizen ticket = $ 450

40 \times r + 10 \times s = 450

40r + 10s = 450 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "r" and "s"</u></em>

Multiply eqn 2 by 2

80r + 20s = 900 --- eqn 3

Subtract eqn 1 from eqn 3

80r + 20s = 900

30r + 20s = 400

(-) ---------------------

50r = 500

<h3>r = 10</h3>

Substitute r = 10 in eqn 1

30r + 20s = 400

30(10) + 20s = 400

300 + 20s = 400

20s = 100

<h3>s = 5</h3>

<em><u>Thus we have:</u></em>

cost of one regular admission ticket = $ 10

cost of one senior citizen ticket = $ 5

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