Help please! Find the length of AB:
2 answers:
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Answer:
The second one; x²+7x+12
Step-by-step explanation:
So, since the beginning lengths of the square is x and x, the area of the square is x².
But then, you add 3 to one length, so that side is now (x+3), and then you add 4 to the width, so that is now (x+4).
Finally, you would multiply them together to get the equation you would use to find the new area.
For this, you would cross-multiply everything together; the x in the length by the x in the width, the x in the length by the 4 in the width, the 3 in the length by the x in the width, and then the 3 in the length by the 4 in the width. Now, all you have to do is add all of these together to get your answer.
Here's the work:
Answer:
See below
Step-by-step explanation:
<h3>Part A</h3>- The graph is attached
- |2x - 4| = mx + 1
It has only one solution when the line mx + 1 is parallel to one part of |2x - 4|.
As per graph, we see m = 2 makes it parallel to y = 2x - 4. This is the only solution.
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Now, as I understand, you are looking for 2 solutions instead of one. It means the line mx + 1 will have 2 points of intersection with the line |2x - 4|.
One of those solutions is attached as well, where m = 1. And you may get many more options for this.
