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2 years ago

Help please! Find the length of AB:

Mathematics

2 answers:

elena-14-01-66 [18.8K]2 years ago

8 0

Answer:

Probably 16 (whatever unit)

Step-by-step explanation:

You divide both sides by three to get x after rewriting the problem.

Bezzdna [24]2 years ago

7 0

Answer:

3x+8

Step-by-step explanation:

won't it just be that because 3x+8 is between A and B

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Consider the sequence:

Vera_Pavlovna [14]

Answer:

a_n = 2^n + 3

Step-by-step explanation:

The first differences have a geometric progression, so the explicit definition will be an exponential function. (It cannot be modeled by a linear or quadratic function.) The above answer is the only choice that is an exponential function.

First differences are ...

(7-5=)2, 4, 8, 16

8 0

2 years ago

Read 2 more answers

Find the Length of ST

vfiekz [6]

Step-by-step explanation:

Consider Similarity and enlargement

To get the enlargement factor,

Take the ratio result of any two similar sides. i.e

PQ/AB = 3.6/2 = 1.8

The enlargement factor is 1.8

To get ST, consider ED then multiply it by the enlargement factor. i.e

= 5 x 1.8

= 9

7 0

2 years ago

2/7 find the reciprocal

Mars2501 [29]

7/2 is the reciprocal of 2/7

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2 years ago

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Find the perimeter of the figure below. <br><br> PLEASE GIVE A EXPLANATION

aleksley [76]

Answer:

Perimeter of the figure = 198.54 feet

Step-by-step explanation:

Given figure comprises a rectangle and two semicircles.

Perimeters of two semicircle = 2πr

Here 'r' = Radius of the circle

Perimeter of two semicircles at the sides of the rectangle = $2\pi (\frac{25}{2})$

= 25π feet

= 78.54 feet

Length of side AB = Length of side CD = 60 feet

Perimeter of the given figure = 2(60) + 78.54

= 198.54 feet

8 0

2 years ago

A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one

d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

$P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855$

The probability that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0

3 years ago