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miss Akunina [59]

2 years ago

15

True or false? An airplane is flying west at 200 km/h. Two hours later, it is flying west at 300 km/h. Its average acceleration

is 100 km/h2.

1 answer:

alex41 [277]2 years ago

4 0

I'm pretty sure its true, not 100%.

You might be interested in

Maru [420]

First, we have to understand the slope-intercept form.

$\large \boxed{y = mx + b}$

A linear function/equation has three forms and the slope-intercept is one of the form. It is also commonly used in Function topic while the other two forms are commonly used in Analytic Geometry.

In the slope-intercept form, the m-term represents the slope while b-term represents the y-intercept of a graph.

<em>W</em><em>h</em><em>i</em><em>c</em><em>h</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>r</em><em>e</em><em>p</em><em>r</em><em>e</em><em>s</em><em>e</em><em>n</em><em>t</em><em>s</em><em> </em><em>a</em><em> </em><em>l</em><em>i</em><em>n</em><em>e</em><em>a</em><em>r</em><em> </em><em>f</em><em>u</em><em>n</em><em>c</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>t</em><em>h</em><em>a</em><em>t</em><em> </em><em>h</em><em>a</em><em>s</em><em> </em><em>a</em><em> </em><em><u>s</u></em><em><u>l</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>o</u></em><em><u>f</u></em><em><u> </u></em><em><u>5</u></em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>a</em><em> </em><em><u>y</u></em><em><u>-</u></em><em><u>i</u></em><em><u>n</u></em><em><u>t</u></em><em><u>e</u></em><em><u>r</u></em><em><u>c</u></em><em><u>e</u></em><em><u>p</u></em><em><u>t</u></em><em><u> </u></em><em><u>o</u></em><em><u>f</u></em><em><u> </u></em><em><u>-</u></em><em><u>6</u></em><em><u>.</u></em>

As you notice the bold, italic and underlined words in the question that I quoted or rewrote. I've just explained that the slope is m-term and y-intercept is b-term.

Therefore, substitute m = 5 and b = -6 in the equation.

$\large{y = mx + b \longrightarrow \bold{y = 5x + ( - 6)}} \\ \large \boxed{ \tt{ \purple{y = 5x - 6}}}$

I hope this helps! Let me know if you have any questions regarding the linear function, don't hestitate to ask. Good luck with your assignment and have a nice day!

5 0

2 years ago

Using the data shown on the graph, which statements are correct

Tomtit [17]

Answer:

B, C, and E

Step-by-step explanation:

Let's consider each option given the graph shown above:

A. The ratio of x/y can be found using any point on the line, say, (5, 6). Thus, ratio of x/y = 5/6, not 6/5.

Option A is not correct.

B. If you check for y/x for any given point along the line, we would have the same result. So the ratio of y/x is consistent. Option B is correct.

C. The graph has a line that runs through the point of origin, so therefore, it represents a proportional relationship.

Option C is correct

D. If option C is correct, then option D is not correct.

E. If option C is correct, then option E is correct.

8 0

3 years ago

What is 31.5 percent of 473?

Anna [14]

31.5% of 473 can be calculated as follows

(31.5/100) * 473
= 14899.5/100
= 148.99

hope it helped

3 0

3 years ago

What is the solution of StartRoot x minus 4 EndRoot + 5 = 2?

Vlad1618 [11]

Answer:

13

Step-by-step explanation:

$\sqrt{x-4}+5=2 \\\\\sqrt{x-4}=-3 \\\\x-4=9 \\\\x=13$

Hope this helps!

6 0

3 years ago

Read 2 more answers

Rebecca and dan are biking in a national park for three days they rode 5 3/4 hours the first day and 6 4/5 hours the second day

AfilCa [17]

Answer:

Rebecca and Dan need to ride $7\frac{9}{20}\ hrs.$ on the third day in order to achieve goal of biking.

Step-by-step explanation:

Given:

Goal of Total number of hours of biking in park =20 hours.

Number of hours rode on first day = $5\frac34 \ hrs.$

So we will convert mixed fraction into Improper fraction.

Now we can say that;

To Convert mixed fraction into Improper fraction multiply the whole number part by the fraction's denominator and then add that to the numerator,then write the result on top of the denominator.

$5\frac34 \ hrs.$ can be Rewritten as $\frac{23}{4}\ hrs$

Number of hours rode on first day = $\frac{23}{4}\ hrs$

Also Given:

Number of hours rode on second day = $6\frac45 \ hrs$

$6\frac45 \ hrs$ can be Rewritten as $\frac{34}{5}\ hrs.$

Number of hours rode on second day = $\frac{34}{5}\ hrs.$

We need to find Number of hours she need to ride on third day in order to achieve the goal.

Solution:

Now we can say that;

Number of hours she need to ride on third day can be calculated by subtracting Number of hours rode on first day and Number of hours rode on second day from the Goal of Total number of hours of biking in park.

framing in equation form we get;

Number of hours she need to ride on third day = $20-\frac{23}{4}-\frac{34}{5}$

Now we will use LCM to make the denominators common we get;

Number of hours she need to ride on third day = $\frac{20\times20}{20}-\frac{23\times5}{4\times5}-\frac{34\times4}{5\times4}= \frac{400}{20}-\frac{115}{20}-\frac{136}{20}$

Now denominators are common so we will solve the numerator we get;

Number of hours she need to ride on third day = $\frac{400-115-136}{20}=\frac{149}{20}\ hrs \ \ Or \ \ 7\frac{9}{20}\ hrs.$

Hence Rebecca and Dan need to ride $7\frac{9}{20}\ hrs.$ on the third day in order to achieve goal of biking.

3 0

2 years ago