$\log _{ 2 }{ \left( 3-x \right) } +\log _{ 2 }{ 5 } =2\log _{ 3 }{ 5 } \\ \\ \log _{ 2 }{ \left( 5\left( 3-x \right) \right) } =\log _{ 3 }{ \left( { 5 }^{ 2 } \right) } \\ \\ { 2 }^{ \log _{ 3 }{ 25 } }=5\left( 3-x \right) \\ \\ { 2 }^{ \log _{ 3 }{ 25 } }=15-5x\\ \\ 5x=15-{ 2 }^{ \log _{ 3 }{ 25 } }\\ \\ x=\frac { 15 }{ 5 } -\frac { { 2 }^{ \log _{ 3 }{ 25 } } }{ 5 } \\ \\ x=3-\frac { { 2 }^{ \log _{ 3 }{ 25 } } }{ 5 }$

8 0

3 years ago

Write the ratio for sin A. A 17 15 с B sin A=

Firlakuza [10]

Answer:

0.292371705 if A=17

0.258819045 if A=15

Step-by-step explanation:

What are all the other options i dont understand

6 0

2 years ago

Simplify -15.4/-4……………………. −3.9 3.9 −4.9 4.9

Dafna1 [17]

It is 3.9 I hope this will help you

8 0

3 years ago