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Marat540 [252]
2 years ago
5

Solve an equation for one variable

Mathematics
1 answer:
AysviL [449]2 years ago
7 0
To solve an equation for one variable, we will utilize PEMDAS ( parentheses, exponents, multiplication/division, add/subtract) but backwards. So we will first add/subtract any numbers to the other side to get the variable by itself. We will then divide/multiply any numbers to get the variable by itself.
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Can dirt be cooked through Newton’s order how is the atoms entitled and which Eliment is directed for cooking
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yes

Step-by-step explanation:

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3 years ago
What is -1/2 times 1/4-3/8?
pav-90 [236]

Answer:

The answer is <em>-0.5</em>

Step-by-step explanation:

6 0
3 years ago
There are 412 students and 20 teachers taking buses on a trip to a museum. Each bus can seat a maximum of 48. Which inequality g
-BARSIC- [3]

The inequality \mathrm{b} \geq \frac{\text { total number of travelers }}{\text { capacity of each bus }} gives the least number of buses, b, needed for the trip. The least number of buses is 9

<u>Solution:</u>

Given that, There are 412 students and 20 teachers taking buses on a trip to a museum.  

Each bus can seat a maximum of 48.  

We have to find which inequality gives the least number of buses, b, needed for the trip?

Now, there are 412 students and 20 teachers, so in total there are 412 + 20 = 432 travelers

<em><u>The number of buses required “b” is given as:</u></em>

\text { (b) } \geq \frac{\text { total number of travelers }}{\text { capacity of each bus }}

\text { So, number of buses required } \geq \frac{432}{48}

Number of buses required ≥  9 buses.

But least number will be 9 from the above inequality.

Hence, the inequality \mathrm{b} \geq \frac{\text {total number of travelers}}{\text {capacity of each bus}} gives least count of busses and least count is 9.

6 0
3 years ago
If x+y=8, y+z=7, and x+z=5, what is the value of x? What is the formula or strategy to approach this question?
joja [24]

The strategy is to work from a system with three variables and three equations down to something with two variables and two equations. In a two variable-two equation system, you can use either substitution or elimination.

First, let's organize the equations.

(1) x + y = 8

(2) y + z = 7

(3) x + z = 5

Now, we'll solve one of (1), (2), and (3) for a variable. The choice is yours, but we'll use equation (3) and solve it for x.

x + z = 5

x = 5 - z.

Now we put this into equation (1). Why (1)? It's the only one of (1) and (2) with x.

x + y = 8

5 - z + y = 8

-z + y = 3

y - z - 3 to rearrange it.

Now look at this new equation - call it (4) and the original (2).

(4) y - z = 3

(2) y + z = 7

This is a system of two equations and two variables. Either substitution or elimination works here - let's use elimination because of the -z and +z.

y - z = 3

y + z = 7

We add them together and we have that 2y = 10. Divide on both sides and y = 5. One variable down, two to go.

Now we go back to original equation (2). Substitute y = 5 to find z.

y + z = 7

5 + z = 7

z = 2.

Two down, one to go. Since we know z = 2, let's put it into (3) and find x. (Equation (1) with y = 5 works fine as well.)

x + z = 5

x + 2 = 5

x = 3

Thus x = 3, y = 5 and z = 2.

3 0
3 years ago
There are 45 students in Lisa's class. 35 of the students are boys and rest are girls
geniusboy [140]
If the question is how many students are girls, than it's ten(10).
8 0
3 years ago
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