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Marat540 [252]
2 years ago
5

Solve an equation for one variable

Mathematics
1 answer:
AysviL [449]2 years ago
7 0
To solve an equation for one variable, we will utilize PEMDAS ( parentheses, exponents, multiplication/division, add/subtract) but backwards. So we will first add/subtract any numbers to the other side to get the variable by itself. We will then divide/multiply any numbers to get the variable by itself.
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Answer:

The suppliers tank won't deliver enough water.

Step-by-step explanation:

Hernando needs at least 75 gallons of water . His supplier has a cylindrical model that has a diameter of 2 ft and height of 3 ft. The volume of water at which his supplier tank can accommodate can be computed as follows .

Since the suppliers model is a cylinder we will use volume of a cylinder formula.

volume = πr²h

where

r = radius = 2/2 = 1 ft

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volume = π × 1² × 3

volume = 3.14 × 3

volume = 9.42  ft³

The suppliers volume of water is 9.42 ft³ and Hernando needs  at least 75 gallons of water.

Since

0.1337 ft³ = 1 gallon of water

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cross multiply

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gallon of water = 70.4562453254

gallon of water = 70.47 gallons.

The suppliers tank won't deliver enough water.

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((46-(4-2)×5))÷2-4=<br> I need to show my work. The answer has to be 22
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