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3 years ago

9-32. Hernando needs to replace the hot water tank at his house. He estimates that his family needs a tank that can hold at

Mathematics

1 answer:

barxatty [35]3 years ago

8 0

Answer:

The suppliers tank won't deliver enough water.

Step-by-step explanation:

Hernando needs at least 75 gallons of water . His supplier has a cylindrical model that has a diameter of 2 ft and height of 3 ft. The volume of water at which his supplier tank can accommodate can be computed as follows .

Since the suppliers model is a cylinder we will use volume of a cylinder formula.

volume = πr²h

where

r = radius = 2/2 = 1 ft

h = height = 3 ft

volume = π × 1² × 3

volume = 3.14 × 3

volume = 9.42 ft³

The suppliers volume of water is 9.42 ft³ and Hernando needs at least 75 gallons of water.

Since

0.1337 ft³ = 1 gallon of water

9.42 ft³ = ? gallon of water

cross multiply

gallon of water = 9.42/0.1337

gallon of water = 70.4562453254

gallon of water = 70.47 gallons.

The suppliers tank won't deliver enough water.

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91.357 decigrams to kilograms

andrezito [222]

the formula for decigrams to kilograms is divide the mass value by 10,000, so the answer would be 0.0091357

3 0

3 years ago

The table below shows the number of cups of coffee people drink a day

Effectus [21]

The mean of a distribution is the sum of the data elements divided by the count of the dataset.

The mean of the distribution is 4

The complete table is given as

$\left[\begin{array}{cc}People & Frequency &0 - 2 & 5 & 3 - 5 & 25 & 6 - 8 & 5\end{array}\right]$

The complete question requires that, we calculate the mean of the dataset

First, we calculate the class midpoint

This is the average of the class interval

For interval 0 - 2,

$x_1 = \frac{0 + 2}{2} = 1$

For interval 3 - 5,

$x_2 = \frac{3 + 5}{2} = 4$

For interval 6 - 8

$x_3 = \frac{6 + 8}{2} = 7$

So, the table becomes

$\left[\begin{array}{ccc}People & x & Frequency &0 - 2 &1 & 5 & 3 - 5 & 4& 25 & 6 - 8& 7 & 5\end{array}\right]$

The mean is then calculated as:

$\bar x = \frac{\sum fx}{\sum f }$

This gives

$\bar x = \frac{5 \times 1 + 25 \times 4 + 5 \times 7}{5 + 25 + 5}$

$\bar x = \frac{140}{35}$

$\bar x = 4$

Hence, the mean of the distribution is 4