Answer:
A)100mL B)50mL C)The second option D)Hypoosmotic Environment
Explanation:
The average Na concentration in the seas and oceans of the world is around 3,5% which mean that in 100 ml of sea water, there is around 3,5 grams of Na.
The weight of one mol of NaCl is 58,44 grams. For 3,5 grams of NaCl, we get 3,5/58,44 = 0,060 mol of NaCl which is 0,060x1000 = 60 mmol/100ml. According to this and the information given in the question about the secretion of the salt glands', if the average sodium concentration is 600mmol/L, we have 60*10 = 600mmol/L so it would take 100 mililiters of water to excrete.
If the average Na concentration of the salt gland's secretion were 300 mmol/L, only 50 mililiters of water would be needed to excrete the same sodium load.
The second option of secretion is hyperosmotic to seawater because the concentration is higher.
Osmoregulation is the process of balancing the amount of water and salt between the body of the organism and its surrounding environment. For salt glands to be advantageous for osmoregulation, they need to be in a hypoosmotic environment.
I hope this answer helps.
Answer:
<h2><u>Carbon</u><u>.</u><u> </u></h2>
Explanation:
<em>Life is based on carbon; organic chemistry studies compounds in which carbon is a central element. The properties of carbon make it the backbone of the organic molecules which form living matter. Carbon is a such a versatile element because it can form four covalent bonds.</em>
<h3><em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u> </u></em><em><u>you</u></em><em><u>⚛</u></em><em><u>.</u></em></h3>
<em><u>Thanks</u></em><em><u>☸</u></em><em><u>.</u></em>
it uses this energy to survive and to hunt for more energy
Answer:
True
Explanation:
The linkage relation of two genes can be determined on the basis of calculating recombination frequency.
If the recombination frequency value is greater than 50% then the genes are not linked and if the value is less than 50% then the genes are linked.
In the given question, the crossover gametes formed will be Ab = 100
and aB= 106.
Therefore,
Since the recombinant frequency value is larger than 50% therefore the genes do not show linkage.
Thus, True is the correct answer.
The convergent boundary or just convergent