1.x^2 +6x - 4 = 6x
X^2 + 6x -4 - 6x = 0
X^2 - 4 = 0
By difference of two squares :
X^2 - 4 = 0 can be written as (x-2) (x+2) = 0
(X-2)=0 therefore x= 2
(X+2)=0 therefore x= -2
2. X^2 - 8x = -6x
X^2 -8x + 6x = 0
X^2 - 2x = 0
X(X-2) = 0
X= 0, X= 2
Answer:
square root of 2, pi, square root of 5, square root of 10, square root of 3, square root of 15
Step-by-step explanation:
Hope this helps you, and good luck in the future :)
Cuz if so, then you just move the whole x term to the right side and divide all the terms on the right side by the coefficient of y
for ex...
3) 4x+4y=16
4y=16-4x (or -4x+16)
y=4-x or -x+4
