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3 years ago

I need help on how much. Will he spend on the cell phone 3 in years

Mathematics

2 answers:

rodikova [14]3 years ago

7 0

Y=30x+150 you put 3 in for x which is y=30(3)+150 y=90+150 y=240

prisoha [69]3 years ago

5 0

Answer:
$1230

Explanation:
First of all, your initial equation is wrong. It should be:
cost = 30m + 150

To find how much 3 years will cost you have to first find how many months are in 3 years:
12 • 3 = 36
Then substitute 36 for m in the equation:
cost = 30(36) + 150
Then solve:
C = 30(36) + 150
C = 1080 + 150
C = 1230

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Jessie is fencing in a rectangular plot outside of her back door so that she can let her dogs out to play. She has 60 feet of fe

DerKrebs [107]

Answer:

Dimensions are length 15 feet and width 30 feet.

Maximum area of the plot is 450 feet².

Step-by-step explanation:

Let the length of the plot = x feet and width = y feet.

Since, the amount of fencing to be applied on the three sides of the plot is 60 feet.

We have,

$2x + y = 60$ i.e. $y=60-2x$

Now, Area of the rectangular plot = Length × Width

i.e. Area of the rectangular plot = $x \times y$

i.e. Area of the rectangular plot = $x\times (60-2x)$

i.e. Area of the rectangular plot = $-2x^2+60x$

<em>Since, the maximum of the quadratic equation $ax^2+bx+c$ will be obtained at $x= \frac{-b}{2a}$ .</em>

Then, the maximum of the area of the plot is at the point $x= \frac{-60}{2\times (-2)}$ i.e. x= 15

Then, maximum area of the rectangular plot = $-2x^2+60x$

i.e. maximum area of the rectangular plot = $-2\times 15^2+60\times 15$

i.e. maximum area of the rectangular plot = -450+900 = 450 feet²

Hence, Maximum area of the plot is 450 feet².

Then, $y=60-2\times 15$ implies $y=60-30$ i.e. y= 30.

Hence, the maximum area is enclosed by the length 15 feet and width 30 feet.

6 0

4 years ago

Need help with trig problem in pic

Sidana [21]

Answer:

a) $cos(\alpha)=-\frac{3}{5}\\$

b) $\sin(\beta)= \frac{\sqrt{3} }{2}$

c) $\frac{4+3\sqrt{3} }{10}\\$

d) $\alpha\approx 53.1^o$

Step-by-step explanation:

a) The problem tells us that angle $\alpha$ is in the second quadrant. We know that in that quadrant the cosine is negative.

We can use the Pythagorean identity:

$tan^2(\alpha)+1=sec^2(\alpha)\\(-\frac{4}{3})^2 +1=sec^2(\alpha)\\sec^2(\alpha)=\frac{16}{9} +1\\sec^2(\alpha)=\frac{25}{9} \\sec(\alpha) =+/- \frac{5}{3}\\cos(\alpha)=+/- \frac{3}{5}$

Where we have used that the secant of an angle is the reciprocal of the cos of the angle.

Since we know that the cosine must be negative because the angle is in the second quadrant, then we take the negative answer:

$cos(\alpha)=-\frac{3}{5}$

b) This angle is in the first quadrant (where the sine function is positive. They give us the value of the cosine of the angle, so we can use the Pythagorean identity to find the value of the sine of that angle:

$cos (\beta)=\frac{1}{2} \\\\sin^2(\beta)=1-cos^2(\beta)\\sin^2(\beta)=1-\frac{1}{4} \\\\sin^2(\beta)=\frac{3}{4} \\sin(\beta)=+/- \frac{\sqrt{3} }{2} \\sin(\beta)= \frac{\sqrt{3} }{2}$

where we took the positive value, since we know that the angle is in the first quadrant.

c) We can now find $sin(\alpha -\beta)$ by using the identity:

$sin(\alpha -\beta)=sin(\alpha)\,cos(\beta)-cos(\alpha)\,sin(\beta)\\$

Notice that we need to find $sin(\alpha)$ , which we do via the Pythagorean identity and knowing the value of the cosine found in part a) above:

$sin(\alpha)=\sqrt{1-cos^2(\alpha)} \\sin(\alpha)=\sqrt{1-\frac{9}{25} )} \\sin(\alpha)=\sqrt{\frac{16}{25} )} \\sin(\alpha)=\frac{4}{5}$

Then:

$sin(\alpha -\beta)=\frac{4}{5}\,\frac{1}{2} -(-\frac{3}{5}) \,\frac{\sqrt{3} }{2} \\sin(\alpha -\beta)=\frac{2}{5}+\frac{3\sqrt{3} }{10}=\frac{4+3\sqrt{3} }{10}$

Since $sin(\alpha)=\frac{4}{5}$

then $\alpha=arcsin(\frac{4}{5} )\approx 53.1^o$

4 0

3 years ago

A number to the 10 power divided by the same number to the 7th power equals 125 what is the number?

Tanzania [10]

The number is 5. All you have to do is make an equation based on the information you have, x will represent the missing number so, x to the power of 10 divided by x to the power of 7 is equal to 125, then solve.

4 0

4 years ago

Read 2 more answers

Given angle 1 is congruent to angle 2 and angle 3 is congruent to angle 4 prove p is parallel to r

Anestetic [448]

What am I answering tho because p can be parallel to r by AA theorem

3 0

3 years ago

What is the greatest number of acute angles that a triangle can contain? A. O B.2 C. 1 D. 3

Fudgin [204]

Answer:

Step-by-step explanation:

We know that a acute angle is a angle whose measure is less than 90°.

Now we know that the sum of all the angles of a triangle is 180°.

Now we have to find such 3 angles which are less than 90° and add up to 180°.

Let we consider a equilateral triangle.

In a equilateral triangle each angle measures 60°<90°.

and also:

60+60+60=180°.

4 0

3 years ago