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iren2701 [21]
2 years ago
5

On a unit circle, what is cos Θ for coordinates

%20%5Cfrac%7B%5Csqrt%7B2%7D%20%7D%7B2%7D%29" id="TexFormula1" title="(\frac{\sqrt{2} }{2} , \frac{\sqrt{2} }{2})" alt="(\frac{\sqrt{2} }{2} , \frac{\sqrt{2} }{2})" align="absmiddle" class="latex-formula">?
A) 0

B) 1

C) \frac{\sqrt{2} }{2}

D) \sqrt{2}
Mathematics
1 answer:
blagie [28]2 years ago
8 0

Answer:  C

Step-by-step explanation:

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What is the equation for the line of reflection that maps the trapezoid onto itself?
kvv77 [185]
The line that maps a figure onto itself is a line of symmetry of the figure.

From the given trapezoid, the line of symmetry of the trapezoid is x = -2.

Therefore, the <span>equation for the line of reflection that maps the trapezoid onto itself</span> is x = -2.
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3 years ago
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Mr Cole has 30 students in his class. He has twice as many girls than boys. What is the ratio of girla to boys?
Elis [28]

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2 years ago
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matrenka [14]

Answer:

Option B - \ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x

Step-by-step explanation:

Given : Expression \ln(\frac{4y^5}{x^2})

To find : Expand each expression ?

Solution :

Using logarithmic properties,

\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B

and \ln (AB)=\ln A+\ln B

Here, A=4y^5 and B=x^2

\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}

\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2

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Using logarithmic property, \logx^a=a\log x

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3 0
2 years ago
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Andru [333]

Answer:

Step-by-step explanation:

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