X and y vary inversely:
y=k/x
y=8/3 when x=8
8/3=k/8
Solving for k:
8(8/3)=k
64/3=k
k=64/3
y=k/x
y=(64/3)/x
y=(64/3)(1/x)
y=64/(3x)
when x=4→y=64/(3x)=64/(3(4))→y=16/3
Answer: Second Option y=64/(3x); 16/3
If the sum of the square of a number plus the triple of the same number equals eighteen, the required numbers are 3 and -6
Let the unknown number be x
The square of the number is expressed as x²
Triple of the unknown number will also be expressed as 3x
Taking the sum of both numbers and equating it to 18 will give;

Factorize the resulting equation:

Hence the required numbers are 3 and -6
Learn more here; brainly.com/question/13805464
Dr/dt= 8cmM-¹
dA/dt = ?
but A= πr²
so dA/dr =2πr
but recall
dA/dt = dA/dr • dr/dt
dA/dt = 2πr • 8cmM-¹
dA/dt = 2×π×39 ×8 = 624cm²M-1
Answer:
265
Step-by-step explanation:
First, you add 9 and 512, then you divide the sum by 2 and you get the answer.