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alexgriva [62]
3 years ago
14

Please help!!!!!!!!!!!!!!!

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
6 0
X and y vary inversely:
y=k/x

y=8/3 when x=8
8/3=k/8

Solving for k:
8(8/3)=k
64/3=k
k=64/3

y=k/x
y=(64/3)/x
y=(64/3)(1/x)
y=64/(3x)

when x=4→y=64/(3x)=64/(3(4))→y=16/3

Answer: Second Option y=64/(3x); 16/3
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Can you please help me?!
Fudgin [204]

Answer:

A and B are correct

Step-by-step explanation:

4 0
2 years ago
The table represents a function. What is the value of f(–1)?
Afina-wow [57]

Answer : C

we need to  the value of f(–1)

Table is given in the question

From the table ,

f(x) = 4 when x= -5, that is f(-5) = 4

f(x) = 0 when x= -1, that is f(-1) =0

f(x)= -1 when x=6, that is f(6) = -1

f(x)= -3 when x=9, that is f(9) = -3

So, the value of f(–1) = 0



3 0
3 years ago
Read 2 more answers
Deposit $500 4% interest 2 years
STatiana [176]

Are you looking for the amount after interest gained? If so I believe the answer would be $40.

500 x 0.04 x 2 = 40

7 0
3 years ago
At the movie theater, childs admission is $6.10. Adult admission is $9.40. On Tuesday four times as many adult tickets as child
Harlamova29_29 [7]

Answer:

The number of children's tickets sold was 27

Step-by-step explanation:

Let

x ----> the number of children's tickets sold

y ----> the number of adult's tickets sold

we know that

6.10x+9.40y=1,179.90 ----> equation A

y=4x ----> equation B

Solve the system by substitution

Substitute equation B in equation A

6.10x+9.40(4x)=1,179.90

solve for x

6.10x+37.6x=1,179.90

43.7x=1,179.90

x=27

therefore

The number of children's tickets sold was 27

8 0
3 years ago
Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }

Note that

\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}

When dividing \sqrt[7]{x^5} by \sqrt[4]{x^2}, we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}

and the result is x^{\frac{3}{14}}=\sqrt[14]{x^3}

2. Given equation 3\sqrt[4]{(x-2)^3} -4=20

Add 4:

3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24

Divide by 3:

\sqrt[4]{(x-2)^3} =8

Rewrite the equation as:

(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3

Hence,

\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18

3 0
3 years ago
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