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2 years ago

John says that because rhombuses do not have perpendicular sides, they cannot be rectangles. Explain

Mathematics

1 answer:

Tema [17]2 years ago

5 0

Rhombuses do have perpendicular sides when you rotate it on its side

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In our hall, there are 10 fans, but only 60% of them are working. Write the number of fans that are out of order?! Pls answerr I

Natali [406]

Answer:

Step-by-step explanation:

There's 10 fans, so each is worth 10%

If 60% of them are not working, that means that 6 fans are not working.

10 - 6 = 4

There are 6 not working fans

and there are 4 working fans

3 0

3 years ago

The number of patients treated at Dr. McCormick’s dentist office each day was recorded for nine days. These are the data: 13, 16

arlik [135]

Hi!

Let's start with the mean.

The mean is all the numbers added together, divided by how many numbers there are.

13+16+16+10+6+12+4+12+16=105
there are 9 numbers so..
105/9 = 11.7

The mean is 11.7

Find the median.

The median is the number in the middle of the data set when the numbers are in numerical order.

4, 6, 10, 12, 12, 13, 16, 16, 16

The median is 12.

Find the mode.

The mode is the number that is repeated the most.

4, 6, 10, 12, 12, 13, 16, 16, 16

The mode is 16

Find the range.

The range is the difference of the smallest number from the biggest number.

16 - 4 = 12

The range is 12

The answer is 11.7, 12, 16, 12

Hope this helps! :)

4 0

4 years ago

Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your

BaLLatris [955]

$f(x,y)=\dfrac{y^3}x$

a. The gradient is

$\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath$

$\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}$

b. The gradient at point P(1, 2) is

$\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}$

c. The derivative of $f$ at P in the direction of $\vec u$ is

$D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}$

It looks like

$\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath$

so that

$\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2$

Then

$D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}$

$\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}$

7 0

4 years ago

A football team has attempted 6 running plays. The change in field position resulting from each play is shown in the table. Runn

Semenov [28]

Answer:

Step-by-step explanation:

-3 +2 +-1 +-2 +-3 +1 = -6 yards total

-6 / 6 = -1 yard per play average

4 0

2 years ago

To the nearest hundredth,what is the value of x ?<br> A)36.08<br> B)41.51<br> C)47.81<br> D)72.88

maks197457 [2]

To solve, you have to use the Cosine of 41°. This is Adjacent side over Hypotenuse. Plug in the known side length and solve for x
Tan 41° = x / 55
x = Tan 41° · 55
x = 47.81 units

This would make the correct answer C. 47.81.

Hope this helps. Good luck! :)

7 0

4 years ago