Answer:
The amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600
Step-by-step explanation:
Let x be the amount in the account at 12% interest
So, 6000-x is the amount in the second account at 7% interest
![SI = \frac{P \times T \times R}{100}](https://tex.z-dn.net/?f=SI%20%3D%20%5Cfrac%7BP%20%5Ctimes%20T%20%5Ctimes%20R%7D%7B100%7D)
First account:![SI=\frac{x \times 1 \times 12}{100}](https://tex.z-dn.net/?f=SI%3D%5Cfrac%7Bx%20%5Ctimes%201%20%5Ctimes%2012%7D%7B100%7D)
Second account : ![SI =\frac{(6000-x) \times 1 \times 7}{100}](https://tex.z-dn.net/?f=SI%20%3D%5Cfrac%7B%286000-x%29%20%5Ctimes%201%20%5Ctimes%207%7D%7B100%7D)
We are given that At the end of the first year he had earned $590 in interest.
So, ![\frac{x \times 1 \times 12}{100}+\frac{(6000-x) \times 1 \times 7}{100}=590\\x=3400](https://tex.z-dn.net/?f=%5Cfrac%7Bx%20%5Ctimes%201%20%5Ctimes%2012%7D%7B100%7D%2B%5Cfrac%7B%286000-x%29%20%5Ctimes%201%20%5Ctimes%207%7D%7B100%7D%3D590%5C%5Cx%3D3400)
So,the amount in the account at 12% interest is $3400
The amount in the second account at 7% interest =6000-x=6000-3400=2600
Hence the amount in the account at 12% interest is $3400 and the amount in the second account at 7% interest is $2600
Answer:
6x² + 4x + 10
Step-by-step explanation:
(2x - 2)(3x + 5)
2x(3x + 5) - 2(3x + 5)
6x² + 10x - 6x + 10
6x² + 4x + 10 ans.
hope this helps you !
X+x+1+x+2=51
3x+3=51
Use inverse operations to solve
subtract 3 from both sides
3x=48
Divide by 3 on both sides
x=16
16, 17, 18
Answer:
0.2x + y -6
Step-by-step explanation:
A and b are already there but to get c you just have to move 6 to the other side by subtracting it from the right side and adding it to the end of the left side.
Answer:
3/12= 1/4
Step-by-step explanation: because you would add the all up for 12 and you have a 3 vanilla's so 3/12= 1/4