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ale4655 [162]
2 years ago
8

Solve the equation n/10 + 7 = 10

Mathematics
2 answers:
Oksanka [162]2 years ago
6 0

\sf \to  \dfrac{n}{10}  + 7 = 10

\\  \\

\sf \to  \dfrac{n}{10}= 10 - 7

\\  \\

\sf \to  \dfrac{n}{10}=3

\\  \\

\sf \to n=3 \times 10

\\  \\

\sf \to n=30

satela [25.4K]2 years ago
5 0

solution;

here

n/10+7=10

or n/10 =10-7

or n/10=3

n=30

Step-by-step explanation:

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5/9+1/9 in simplest form. Explain.
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Answer:

2/3

Step-by-step explanation:

5/9 + 1/9

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Answer:

The answer is,

r =  \frac{3t}{t - 1}

Step-by-step explanation:

t =  \frac{r}{ r - 3}

Firstly, you have to get rid of fraction by multiplying (r-3) to both side and expand out:

t × (r-3) = r/(r-3) × (r-3)

rt - 3t = r

Then you have to move all the "r" variables to one side and other variables to the other side:

rt - r = 3t

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4 0
3 years ago
What’s is 17 subtract 75
Taya2010 [7]
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6 0
3 years ago
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Step-by-step explanation:

7 0
2 years ago
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A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of sta
nalin [4]

Answer:

Option 2 - Approximately 24–36 pounds

Step-by-step explanation:

Given : A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of standard Eskimo dogs are normally distributed.

To find : What range of weights would 99.7% of the dogs have?

Solution :

The range of 99.7% will lie between the mean ± 3 standard deviations.

We have given,

Mean weight of Eskimo dogs is \mu=30

Standard deviation of Eskimo dogs is \sigma=2

The range of weights would 99.7% of the dogs have,

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3 years ago
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