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vazorg [7]
3 years ago
7

Solve 2x squared + 13x equals to 15​

Mathematics
2 answers:
sergejj [24]3 years ago
5 0

Answer:

x=1, x=-15/2

Step-by-step explanation:

xxMikexx [17]3 years ago
4 0
Hi there hope you can see the pic please let me know if the answer is wrong and I will try to redo it for you

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PLEASE HELP WILL MARK BRAINLIEST
MrRissso [65]

Answer:

What is the question?

Step-by-step explanation:

3 0
3 years ago
The length of the base of an isosceles triangle is x. The length of a leg is 4x-6. The perimeter of the triangle is 60. Find x.
lbvjy [14]

Answer:

Perimeter of a triangle = add all sides

Both the legs of the isosceles triangle are always EQUAL.

x+4x-6+4x-6 = 60

9x-12 = 60

9x = 60+12

9x = 72

x = 8

3 0
2 years ago
Use the​ F-scale measurements of tornadoes listed in the accompanying table. The range of the data is 4.0. Use the range rule of
Tcecarenko [31]

Answer:

Within 0.5 of ;

is not ;

Step-by-step explanation:

Given the data:

The actual standard deviation, = 1

;

The range rule of thumb to estimate the value if standard deviation is ;

Estimated standard deviation = Range / 4

The range = (maximum - minimum) values

The estimated standard deviation = 4 / 4 = 1

Hence, the estimated standard deviation is with 0.5 of the actual standard deviation, Thus, the estimated standard deviation is not substantially different from the actual standard deviation.

4 0
3 years ago
The table lists how poverty level income cutoffs​ (in dollars) for a family of four have changed over time. Use the midpoint for
frez [133]

The poverty level cutoff in 1987 to the nearest dollar  was $10787.

<h3>How to find a midpoint?</h3>

The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is: \mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right).

For solving this exercise, first you need plot the points in a chart. See the image.

Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).

\mathrm{Midpoint\:of\:}\left(1980,8429),\:\left(1990,13145):\quad \left(\frac{1990+1980}{2},\:\:\frac{13145+8429}{2}\right)\\\\ \\

\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\left(\frac{1990+1987}{2},\:\frac{13145+3843}{2}\right)\\ \\ =\left(\frac{3977}{2},\:\frac{21574}{2}\right)

\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\=(\frac{3977}{2},10787)

The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar  was $10787.

Read more about the midpoint segment here:

brainly.com/question/11408596

7 0
2 years ago
Can please answer these 3 questions
kupik [55]
So it would be 32 lol if
6 0
2 years ago
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