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3 years ago

1. Slope = (7,-1) and 12,-2)

Mathematics

1 answer:

Evgen [1.6K]3 years ago

6 0

Answer: -1/5

Step-by-step explanation:

the equation to solve slope with two points is the y coordinate in the second point minus the y coordinate in the first point over the x coordinate in the second point minus the x coordinate in the first point so this one would be

(-2 - -1)/(12-7)

On the top you subtract a negative it becomes a positive and you get -1/5

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Jack birthday is in 6 weeks how many day is it until jacks birthday? Complete the explanation on how you could use a number line

Pie

Answer:

42 days

Step-by-step explanation:

1 week equals 7 days

7 × 6 = 42

4 0

3 years ago

Find the quotient of -1 4/5 and 3 1/4

abruzzese [7]

The quotient of -1 4/5 and 3 1/4 = (<span>-1 4/5) / ( 3 1/4)

= [ - (5 * 1 + 4) / 5 ] / [ (3 * 4 + 1) / 4 ]

= [ -9 / 5 ] / [ 13 / 4 ]

= [ -9 / 5 ] * [ 4 / 13 ]

= [ -9 * 4 ] / [ 5 * 13 ]

= -36/65

another way is to do it separately first: </span>-1 4/5 and 3 1/4

-1 4/5 = -(1 + 4/5)

= -(5/5 + 4/5)

= -9/5

3 1/4 = 3 + 1/4

= 3*4/4 + 1/4

= 12/4 + 1/4

= 13/4

so (-1 4/5) / ( 3 1/4)

= (-9/5) / (13/4)

= (-9/5) * (4/13)

= (-9*4) / (5*13)

= -36/65

3 0

3 years ago

Read 2 more answers

6^3=216. Using exponents, write three more expressions whose value is 216.

faltersainse [42]

Answer:

$216^1$

$(2^3)(3^3)$

$(2*2^2)(3*3^2)$

Step-by-step explanation:

To solve this exercise you must keep on mind that according to the exponents rules:

$(a^m)(a^n)=a^{(m+n)}$

$a^1=a$

1) Therefore, you can write 216 as:

$216^1$

Because: $216^1=216$

2) Descompose the number 216 into its prime factors, then:

$216=2*2*2*3*3*3=(2^3)(3^3)$

Then you can write the number 216 as $(2^3)(3^3)$

3) You can also write 216 as following:

$(2*2^2)(3*3^2)$

7 0

4 years ago

Can someone and give me the right answer

kolezko [41]

The 1st option is your answer,

because to solve c, the -11 and 11 = 0, so your left with adding 23 and 11, then you divide -4 on both sides to get the variable (x) by itself

And for f, you only need to divide -4 on both sides to get x by itself.

6 0

3 years ago

Find the area of the following regions, expressing your results in terms of the positive integer n â‰¥ 2. The region bounded by

cluponka [151]

Answer:

The area of the searched region is $A= a+b+ \frac{2n}{n+1}- \frac{n(a^{\frac{n+1}{n} }+b^{\frac{n+1}{n} }) }{n+1}-2$

Step-by-step explanation:

If you want to find the area of a region bounded by functions f(x) and G(x) between two limits (a,b), you have to do a double integral. you must first know which of the functions is greater than the other for the entire domain.

In this case, for 0<x<1, f(x)<g(x)

while for 1<x, g(x)<f(x).

Therefore if our domain is all real numbers superior to 0 (where the limit 0<a<1 and 1<b), we have to do 2 integrals:

A=A(a<x<1)+A(1<x<b)

$A(a$

$A(1$

$A=a-1 +\frac{n}{n+1} - \frac{na^{\frac{n+1}{n} } }{n+1} + b-1 + \frac{n}{n+1} - \frac{nb^{\frac{n+1}{n} } }{n+1} = a+b+ \frac{2n}{n+1} - \frac{n(a^{\frac{n+1}{n} }+b^{\frac{n+1}{n} }) }{n+1} -2$

3 0

3 years ago