Seven hundred twenty centiliters is how many liters?.

Tell whether the triangle with the given side lengths is a right triangle.<br> 12cm, 35cm, 37cm

Vlada [557]

Answer:

Yes

Step-by-step explanation:

Pythagorean theorem states that for right triangles a^2 + b^2 = c^2, which is true for this as a^2 = 1225 + 144 (b^2) = 1369,

1369 = 37^2

7 0

3 years ago

Puzzle 5

sineoko [7]

Answer:

Hey did you get the answer to it please let me know girly

Step-by-step explanation:

8 0

3 years ago

9.84615384615 in a fraction

choli [55]

Answer:

Step-by-step explanation:

128/13

3 0

4 years ago

A mine extracts 2 metric tons of coal in an hour. The mine uses 14 ton of the extracted coal every hour to generate electricity

olga nikolaevna [1]

This sounds like a very poor business model right from the beginning.
The mine continuously operates at a loss, and it has nothing to sell.

If it uses 14 tons an hour just to keep running, and it produces 2 tons
an hour, then it doesn't take a business genius to point out that this
operation is rapidly digging itself straight into the ground.

I'm guessing that there was a major mistake made during the copying
of the problem.

6 0

3 years ago

Read 2 more answers

An automobile owner found that 20 years ago, 72% of Americans said that they would prefer to purchase an American automobile. He

LenaWriter [7]

Answer:

$z=\frac{0.884 -0.72}{\sqrt{\frac{0.72(1-0.72)}{43}}}=2.395$

Now we can find the p value taking incount that we are using a bilateral test

$p_v =2*P(z>2.395)=0.01662$

Since the p value is lower than the significance level of 0.1 we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of Americans that they would prefer an American automobile is significantly different from 0.72 and then the claim is correct

Step-by-step explanation:

Information given

n=43 represent the random sample taken

X=38 represent the Americans who they would prefer an American automobile

$\hat p=\frac{38}{43}=0.884$ estimated proportion of Americans that they would prefer an American automobile

$p_o=0.72$ is the value that we want to check

$\alpha=0.1$ represent the significance level

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to verify if the percentage of Americans that they would prefer an American automobile today differs from 72%, then the system of hypothesis are:

Null hypothesis: $p=0.72$

Alternative hypothesis: $p \neq 0.72$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the data given we got:

$z=\frac{0.884 -0.72}{\sqrt{\frac{0.72(1-0.72)}{43}}}=2.395$

Now we can find the p value taking incount that we are using a bilateral test

$p_v =2*P(z>2.395)=0.01662$

Since the p value is lower than the significance level of 0.1 we have enough evidence to reject the null hypothesis and we can conclude that the true proportion of Americans that they would prefer an American automobile is significantly different from 0.72 and then the claim is correct

5 0

3 years ago