Question

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Answer 1

Right triangles are triangles that have the measure of one angle to be 90 degrees

How to calculate the missing parts

a. A = 40°10'13", hypotenuse = 402.36 ft

Convert the angle to degrees

$A=40.17^o$

Start by calculating the opposite side using the following sine ratio

$\sin(A) = \frac{Opposite}{Hypotenuse}$

So, we have:

$\sin(40.17) = \frac{Opposite}{402.36}$

Cross multiply

$Opposite = 402.36 * \sin(40.17)$

$Opposite = 259.55$

The adjacent is then calculated using the following cosine ratio

$\cos(A) = \frac{Adjacent}{Hypotenuse}$

So, we have:

$\cos(40.17) = \frac{Adjacent}{402.36}$

Cross multiply

$Adjacent = 402.36 * \cos(40.17)$

$Adjacent = 307.46$

Hence, the missing parts are:

Adjacent = 307.46 and Opposite = 259.55

b. A = 62°09'15", hypotenuse = 338.74 m

Convert the angle to degrees

$A=62.15^o$

Start by calculating the opposite side using the following sine ratio

$\sin(A) = \frac{Opposite}{Hypotenuse}$

So, we have:

$\sin(62.15) = \frac{Opposite}{338.74}$

Cross multiply

$Opposite = \sin(62.15) *338.74$

$Opposite = 299.50$

The adjacent is then calculated using the following cosine ratio

$\cos(A) = \frac{Adjacent}{Hypotenuse}$

So, we have:

$\cos(62.15) = \frac{Adjacent}{338.74}$

Cross multiply

$Adjacent = \cos(62.15) * 338.74$

$Adjacent = 158.25$

Hence, the missing parts are:

Adjacent = 158.25 and Opposite = 299.50

c. A = 36°22'10", adjacent side = 360.41 ft

Convert the angle to degrees

$A=36.37^o$

Start by calculating the hypotenuse using the following cosine ratio

$\cos(A) = \frac{Adjacent}{Hypotenuse}$

So, we have:

$\cos(36.37) = \frac{360.41}{Hypotenuse}$

Make Hypotenuse the subject

$Hypotenuse = \frac{360.41}{\cos(36.37)}$

$Hypotenuse = 447.60$

The opposite side is then calculated using the following cosine ratio

$\sin(A) = \frac{Opposite}{Hypotenuse}$

So, we have:

$\sin(36.37) = \frac{Opposite}{447.60}$

Cross multiply

$Opposite = 447.60 * \sin(36.37)$

$Opposite = 265.43$

Hence, the missing parts are:

Hypotenuse = 447.60 and Opposite = 265.43

d. Hypotenuse = 428.29 m, opposite side =397.06 m

The adjacent is calculated as:

$Adjacent = \sqrt{Hypotenuse^2 - Opposite^2$

So, we have:

$Adjacent = \sqrt{428.29^2 - 397.06^2$

$Adjacent = 160.55$

Hence, the missing part is:

Adjacent = 160.55

e. Hypotenuse = 409.31 ft, adjacent side = 274.82 ft

The opposite is calculated as:

$Opposite= \sqrt{Hypotenuse^2 - Adjacent ^2$

So, we have:

$Opposite= \sqrt{409.31^2 - 274.82^2$

$Opposite= 303.33$

Hence, the missing part is:

Opposite= 303.33

f. Opposite side = 375.82 m, adjacent side= 276.05 m

The hypotenuse is calculated as:

$Hypotenuse= \sqrt{Opposite^2 + Adjacent ^2$

So, we have:

$Hypotenuse= \sqrt{375.82^2 + 276.05^2$

$Hypotenuse= 466.31$

Hence, the missing part is:

Hypotenuse= 466.31

Read more about right triangles at:

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