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dsp73
4 years ago
12

Which statement is true about the ranges for the box plots?A number line goes from 0 to 16. Morning's whiskers range from 3 to 1

5, and the box ranges from 5 to 12. A line divides the box at 8. Afternoon's whiskers range from 4 to 16, and the box ranges from 8 to 15. A line divides the box at 14.
a. The range of the Morning box plot is the same as the range of the Afternoon box plot.
b. The range of the Morning box plot is 1 less than the range of the Afternoon box plot.
c. The range of the Morning box plot is 1 more than the range of the Afternoon box plot.
d. The range of the Morning box plot is 2 less than the range of the Afternoon box plot
Mathematics
2 answers:
Mnenie [13.5K]4 years ago
8 0

Answer:

The correct answer is A. The range for the Morning box plot is the same as the range for the Afternoon box plot.

I just took the test and this was the right answer

Zepler [3.9K]4 years ago
4 0

Answer: A

Step-by-step explanation: just took the quiz

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If x=4 and y=10 what is the constant of proportionality
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Answer:

k=2.5

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Constant of Proportionality is k=y/x

k = 10/4 = 2.5

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Simplify the expression (3/7)^2
STatiana [176]

Answer: 9/49

3/49. it doesn't simplify more, unless you're looking for the decimal value.


5 0
3 years ago
Read 2 more answers
Help! Based on the given information, what can you conclude and why?
DochEvi [55]

Answer: \triangle HIJ \cong \triangle LKJ

Step-by-step explanation:

Given: ∠H ≅∠L and line HJ congruent to Line JL.

Since, In triangles HIJ and LKJ,

∠H ≅ ∠L

HJ ≅ JL

And, ∠HJI ≅ ∠ LJK

Therefore, By ASA postulate,

Δ HIJ ≅ Δ LKJ

This is why Option first is correct.

Note: Option third ΔHIJ≅ΔJKL is not correct,

Because,  HI≠JK



6 0
3 years ago
Felix was given $125 for his birthday from his grandmother. He plans to put this money toward the purchase of a $250 skateboard.
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Its is B! like I just worked it out.

4 0
3 years ago
A model rocket is launched directly upward at a speed of 28 meters per second from a height of 12 meters. The function f(t) = -
Jet001 [13]

Answer:

6.11 seconds

Step-by-step explanation:

Given

f(t) = -4.9t^2 + 28t + 12

Required

When will it hit the ground?

When it hits the ground, f(t) = 0.

So, we have:

0 = -4.9t^2 + 28t + 12

Solve quadratic equation using formula

t = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

t = \frac{-28 \± \sqrt{28^2 - 4*-4.9*12}}{2*-4.9}

t = \frac{-28 \± \sqrt{1019.2}}{-9.8}

t = \frac{-28 \± 31.92}{-9.8}

Split

t = \frac{-28 + 31.92}{-9.8} or t = \frac{-28 - 31.92}{-9.8}

t = \frac{3.92}{-9.8} or t = \frac{-59.92}{-9.8}

t = -0.4 or t = 6.11

Time can not be negative. So:

t = 6.11

6 0
3 years ago
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