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horsena [70]
2 years ago
11

What is the equation of the line????????

Mathematics
2 answers:
IrinaVladis [17]2 years ago
8 0

Answer:

y=1/2x+2

Step-by-step explanation:

The equations come in the form of y=mx+c, where m is the gradient and c is the y-intercept. Looking at the graph we know that the y-intercept is (0,2), so that rules out options B and C.

To find the gradient is a little more tricky, but we can follow the formula:

\frac{rise}{run}, where rise is the vertical value and run is the horizontal value

So we sub in our values:

\frac{2}{4}

And simplify:

\frac{1}{2}

So now we sub in our new found values into y=mx+c:

y=1/2x+2

ki77a [65]2 years ago
7 0

Answer: y = x/2 + 2 which is the 4th option from the top

Step-by-step explanation:

First find the slope which is (0-2)/(-4-0) = 2/4 = 1/2

So it's y = x/2 + c

Substituing (-4,0) into the equation we get

0 = -4/2 + c

0 = c-2

c = 2

So the equation is y = x/2 + 2 which is the 4th option from the top

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alisha [4.7K]

Answer:

d=3\sqrt{2}\ units

Step-by-step explanation:

<u><em>The complete question is</em></u>

Line L contains points (3, 5) and (7, 9). Points P has coordinates (2, 10). Find the distance from P to L

step 1

Find the equation of the line L contains points (3,5) and (7,9)

<em>Find the slope</em>

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the given values

m=\frac{9-5}{7-3}

m=\frac{4}{4}=1

<em>Find the equation of the line in point slope form</em>

y-y1=m(x-x1)

we have

m=1\\point\ (3,5)

substitute

y-5=(1)(x-3)

isolate the variable y

y=x-3+5

y=x+2 -----> equation A

step 2

Find the equation of the perpendicular line to the given line L  that passes through the point P

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal

so

The slope of the given line L  is m=1

The slope of the line perpendicular to the given line L  is

m=-1

<em>Find the equation of the line in point slope form</em>

y-y1=m(x-x1)

we have

m=-1\\point\ (2,10)

substitute

y-10=-(x-2)

isolate the variable y

y=-x+2+10

y=-x+12 ----> equation B

step 3

Find the intersection point equation A and equation B

y=x+2 -----> equation A

y=-x+12 ----> equation B

solve the system by graphing

The intersection point is (5.7)

see the attached figure

step 4

we know that

The distance from point P to the the line L is equal to the distance between the point P and point (5,7)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

(2,10) and (5,7)

substitute

d=\sqrt{(7-10)^{2}+(5-2)^{2}}

d=\sqrt{(-3)^{2}+(3)^{2}}

d=\sqrt{18}\ units

simplify

d=3\sqrt{2}\ units

see the attached figure to better understand the problem

6 0
3 years ago
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