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3 years ago

State the slope and the y- intercept for the graph of 2x + y = 3.

1 answer:

4 0

We need to put ur equation in y = mx + b form ...and the m will be ur slope and the b will be ur y int
so basically, we solve for y...

2x + y = 3....subtract 2x from both sides
y = -2x + 3

y = mx + b
y = -2x + 3......slope(m) = -2 and y int (b) = 3 <==

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FP!!!!!!!!!!!!!!!!!!! if ur up ( 10 x 8 ) + 150

taurus [48]

Answer:

220

Step-by-step explanation:

first we have by Bracket of BODMAS rule then we have to multiply 10 *8 = 80

first we have by Bracket of BODMAS rule then we have to multiply 10 *8 = 80then we have to open bracket 80 +150

first we have by Bracket of BODMAS rule then we have to multiply 10 *8 = 80then we have to open bracket 80 +150 = 220

(10*8) +15

Solution

Solution= (80) +150

Solution= (80) +150= 80+150

Solution= (80) +150= 80+150=. 220

Solution= (80) +150= 80+150=. 220

8 0

2 years ago

Read 2 more answers

What is the value of z if z/4 = 12

Digiron [165]

Answer:

z = 48 :)

Step-by-step explanation:

z ÷ 4 = 12

So, all you need to do is multiply 12 by four, to get z- 48

hope this helped!

5 0

3 years ago

Read 2 more answers

Unit 3, Lesson 7

aksik [14]

Answer:

Find the complete table in attached file.

Step-by-step explanation:

Find the Incomplete table in attached file

Given:

A car travels 55 miles per hour for 2 hours.

So the speed of the car 55 miles per hour is constant for 2 hours.

Using speed formula.

$Speed=\frac{distance}{time}$

Second row.

From the second row of the table $time = \frac{1}{2}=0.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.

$Speed=\frac{distance}{time}$

$55=\frac{distance}{0.5}$

$distance = 55\times 0.5$

$distance = 27.5\ mi$

Third row.

From the third row of the table $time =1\frac{1}{2}=\frac{3}{2} = 1.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.

$Speed=\frac{distance}{time}$

$55=\frac{distance}{1.5}$

$distance = 55\times 1.5$

$distance = 82.5\ mi$

Fourth row.

From the fourth row of the table $distance =110\ miles$ and speed is constant $speed = 55\ mi/hr$ , so we need to find time.

$Speed=\frac{distance}{time}$

$time=\frac{distance}{speed}$

$time=\frac{110}{55}$

$time = 2\ sec$

Therefore we complete the table from the above calculation.

8 0

3 years ago

Factor each expression. Problem: 2p^3 + 6p^2 + 3p + 9 Answer: (p + 3) (2p2 + 3)

oee [108]

Factor by grouping
$2p^3 + 6p^2 + 3p + 9$
$2 p^3+6 p^2+3 p+9=\left(2 p^3+6 p^2\right)+(3 p+9)=\left(2 p^2\right) (p+3)+3 (p+3)$
$2 p^2 (p+3)+3 (p+3)$
$(p+3) \left(2 p^2+3\right)$

4 0

2 years ago

Find in the triangle. Round to the nearest degree. a. 45° C. 60° b. 59° d. 42°

aleksklad [387]

Answer:

Theta = 59 degrees

Step-by-step explanation:

Here, we want to get the value of the marked angle

To do this, we use the appropriate trigonometric ratio

From what we have,

The side 42 ft is adjacent the angle given

The side facing the right angle is 82 ft

The trigonometric ratio that connects the adjacent and the hypotenuse is cosine. It is the ratio of the adjacent to the hypotenuse

Cos theta = 42/82

theta = cos^-1 0.5122

theta= 59.189

To the nearest degrees, this is 59 degrees

6 0

2 years ago