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spin [16.1K]
2 years ago
12

The details about Aunt Grace in lines 15-17 ("my clumsy floor") suggest that, to the speaker, Aunt Grace is

Advanced Placement (AP)
1 answer:
d1i1m1o1n [39]2 years ago
6 0

The details about Aunt Grace in lines 15-17 ("my clumsy floor") suggest that, to the speaker, Aunt Grace is; An embodiment of the messiness of reality vs the order that art sometimes imposes

<h3>American Poetry</h3>

This question is taken from the book titled An Ear to the Ground: An Anthology of Contemporary American Poetry.

Now, the statement from the book is that clumsy aunty grace chased the ones she had dropped on the linoleum floor.

From that statement and when considering other statements around that story, we can tell that it was describing aunty grace as an embodiment of the messiness of reality vs the order that art sometimes imposes.

Read more about American Poetry at; brainly.com/question/19943780

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At a large university, 20% of a random sample of male students have an overall grade point average (GPA) of 3.5 or higher. A ran
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H0:p1 − p2 = 0 and Ha:p1 − p2 ≠ 0

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Null hypothesis would be there not being a difference, so the difference would be 0.

Alternative hypothesis would be that there is a difference. However, the president of the university does not want to determine whether more males than females, or more females than males, get a GPA of 3.5 or higher, so the alternative hypothesis is =/= 0.

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A test of the null hypothesis H0: μ = 0 gives test statistic z = 1.8. a) What is the P-value if the alternative is Ha: μ &gt; μ0
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According to the result of the test statistic, the p-values are given by:

a) 0.0352.

b) 0.9648.

c) 0.0704.

<h3>How to find the p-value of a test?</h3>

It depends on the test statistic z, as follows.

  • For a left-tailed test, it is the area under the normal curve to the left of z, which is the <u>p-value of z</u>.
  • For a right-tailed test, it is the area under the normal curve to the right of z, which is <u>1 subtracted by the p-value of z.</u>
  • For a two-tailed test, it is the area under the normal curve to the left of -z combined with the area to the right of z, hence it is <u>2 multiplied by 1 subtracted by the p-value of z.</u>

In this problem, the test statistic is z = 1.8, which has a p-value of 0.9648.

Item a:

Right-tailed test, hence the p-value is of 1 - 0.9648 = 0.0352.

Item b:

Left-tailed test, hence the p-value is of 0.9648.

Item c:

Two-tailed test, hence the p-value is of 2 x (1 - 0.9648) = 2 x 0.0352 = 0.0704.

You can learn more about p-values at brainly.com/question/13873630

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