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2 years ago

Which of the following is the equation for the graph shown?

Mathematics

1 answer:

masha68 [24]2 years ago

8 0

The equation of the circle shown is:

$x^2 + y^2 = 100$

<h3>What is the equation of a circle?</h3>

The equation of a circle of center $(x_0, y_0)$ and radius r is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

From the graph, it can be seen that the center of the circle is (0,0), thus $(x_0, y_0) = (0,0)$ and the radius is of r = 10, hence the equation is:

$x^2 + y^2 = 100$

You can learn more about the equation of a circle at brainly.com/question/24307696

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Exactly 9 years ago, Jeri opened a bank account that earned 2% interest each year. If the account now has $215.12, how much did

MAVERICK [17]

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3 years ago

Suppose that MNO is isosceles with base NM. Suppose also that =m∠N+4x7° and =m∠M+2x29°. Find the degree measure of each angle in

chubhunter [2.5K]

Answer:

m∠N = 51°

m∠M = 31°

m∠O = 98°

Step-by-step explanation:

It is given that ΔMNO is an isosceles triangle with base NM.

m∠N = (4x + 7)° and m∠M = (2x + 29)°

By the property of an isosceles triangle,

Two legs of an isosceles triangle are equal in measure.

ON ≅ OM

And angles opposite to these equal sides measure the same.

m∠N = m∠M

(4x + 7) = (2x + 29)

4x - 2x = 29 - 7

2x = 22

x = 11

m∠N = (4x + 7)° = 51°

m∠M = (2x + 9)° = 31°

m∠O = 180° - (m∠N + m∠M)

= 180° - (51° + 31°)

= 180° - 82°

= 98°

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3 years ago

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goldenfox [79]

Answer:

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Step-by-step explanation:

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3 years ago

For the line segment whose endpoints are R(1, 2) and S(6, 7), find the y value for the point located 3 ov`er 4 the distance from

Mrac [35]

Answer:

23/4

Step-by-step explanation:

This means that it is 3/4 of the distance in the x <u>and</u> y coordinates, so it is 3/4 of the way from 2 to 7, and since this is a difference of 7-2=5, then it is 2 + (5 * 3/4) or 2 + 15/4 or 23/4.

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3 years ago

Determine the values of the constants b and c so that the function given below is differentiable. f(x)={2xbx2+cxx≤1x>1

Lera25 [3.4K]

Assuming the function is

$f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}$

For $f(x)$ to be differentiable, it necessarily has to be continuous. For this condition to be met, we need

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)$
$\iff\displaystyle\lim_{x\to1}2x=\lim_{x\to1}(bx^2+cx)$
$\iff2=b+c$

For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have

$f'(x)=\begin{cases}2&\text{for }x1\end{cases}$

$\displaystyle\lim_{x\to1^-}2=\lim_{x\to1^+}(2bx+c)$
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Now we solve for $b$ and $c$ :

$\begin{cases}b+c=2\\2b+c=2\end{cases}\implies b=0,c=2$

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3 years ago