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Fittoniya [83]
3 years ago
10

A video game has three villains who appear on screen at different intervals. One villain appears every 5 seconds, a second villa

in appears every 10 seconds, and a third villain appears every 16 seconds. How much time passes between occasions when all three villains appear at the same time?
Mathematics
2 answers:
expeople1 [14]3 years ago
8 0

This question is simply asking: What is the LCM(5,10,16). We can solve this by finding the prime factors of these numbers and then only consider the largest one of them. What I mean by that is this:

5=5\\ 10=5*2\\ 16=2^4 \implies \\ \lcm{5,10,16}=5*2^4=80

So, the second time these villains appear together (after 0), is at 80 seconds, and we can conclude that it takes 80 econds for the villains to appear after they've last appeared.

maks197457 [2]3 years ago
5 0
We find the LCM of 5, 10 and 16.
To do so, we divide 5 and 10 by a prime factor, 5. This leaves us to 1, 2 and 16. Then, we can use a prime factor, 2 to divide 2 and 16 into 1 and 8, then it'll become 1, 1 and 8, which is the common factor.

Then we multiply everything together
5, 2 (the two prime factors we used) and also 1, 1 and 8.
5*2*1*1*8 = 80

We can conclude that the all 3 villains appear at the same time every 80 seconds.
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Number 8 please can you write and equation
tigry1 [53]
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3 0
3 years ago
Which equation matches the statement below?
kvasek [131]

Answer:

3(n-5)=2n+16

Step-by-step explanation:

3 lots of 'n' <em>and </em>5 means 3 times both values so these values are put into a bracket with a common multiplier (ie. the 3)

3(5 - n)

16 more than 2 lots of 'n' means that n has to be doubled. n + n = 2n. add 16 to this and we have

2n + 16

if these values are both equal (hence why they are in an equation) then all that is needed is for them to be set equal alongside each other.

3(n-5) = 2n+16

:)

8 0
1 year ago
1/5x-2/3y=30 when y=15
dolphi86 [110]

Answer:

Step-by-step explanation:

<u>Step 1:  Set y to 15 and solve</u>

<u />\frac{1}{5}x - \frac{2}{3}*15=30

\frac{1}{5}x-10=30

<em>Add 10 to both sides</em>

<em />\frac{1}{5}x-10+10=30+10

\frac{1}{5}x=40

<em>Multiply both sides by 5</em>

<em />\frac{1}{5}x*\frac{5}{1}=40*\frac{5}{1}

x=200

Answer:  x=200

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3 years ago
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a_sh-v [17]
1/242x^2 is your answer
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If y varies directly as x, what is the value of y in these ordered pairs?<br> (8, 4) and (4, y)
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We notice that the value of x its been halved. So y varies with x so y value also has to be halved so y= 2
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