Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.
Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
Answer:
the required matrix is can be given as
Answer:
you simplify the fractions then you cross multiply
Step-by-step explanation:
1/2 * 4/2 you multiply 1 and 4 and you get 4/4 which is equal to 1
The way to solve this is to do 5 1/5 divide by 2.5.
2.08 minutes
Answer:
We have sin² x + cos² x =1 for all real x.
Therefore, sin² x = 1 – cos² x = 1 – (8/17)² = 1 – 64/289 = 225/289 = (15/17)².
However, remember that if x² = a², then x can be +a or –a.
Therefore, sin x can be either –15/17 or +15/17.
Everyone but Anirban so far has forgotten the negative solution.
Step-by-step explanation:
Given that sinθ=817 and cosθ<0 , we have: cosθ=−√1−sin2θ. cosθ=−√1−(817)2. cosθ=−√1−64289.
