The sum of two numbers is 196. One number is 64 more than the other. Find the numbers.
2 answers:
Answer:
Step-by-step explanation:
Hi there!
Let one of the number be "x" then the next number is x+64.
According to the question,
The sum of two numbers is 196.
i.e x + (x+64) = 196
or, 2x +64 = 196
Subtract 64 from both sides,
2x +64-64 = 196 - 64
2x = 132
Divide both sides by 2,
=
x = 66
And x+64 = 66+64 = 130
Therefore, the one number was 66 and another was 130.
Hope it helps!
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Answer:
m∠1 + m∠3 = m∠2 + m∠4
Step-by-step explanation:
In the figure attached,
In the given trapezoid if two sides AB and CD are parallel and AD is a transverse,
m∠1 + m∠3 = 180°
Similarly, if AB and CD are parallel and BC is a transverse,
m∠2 + m∠4 = 180°
Therefore, m∠1 + m∠3 = m∠2 + m∠4 is the relation between these angles.
