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Monica [59]
3 years ago
7

Please Help if you can! There are 2 red gumdrops and 3 green gumdrops in a small jar. Also, 3 pieces of butterscotch candy and 2

pieces of cinnamon candy are in another jar. If Craig draws one piece of candy from each jar without looking, what's the probability that he will get a red gumdrop and a piece of butterscotch candy? The Answer choices are 6/25, 1/2, 4/25, or 1/5! Thank you!
Mathematics
1 answer:
attashe74 [19]3 years ago
5 0
I think it would be 6/25 because you have 2/5 chance and a 3/5 chance,
2 × 3 = 6
--- --- ---
5 × 5 = 25

I hope this helps ♡ chyna
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Please help I'm having a small brain moment
ahrayia [7]

Answer:

Option 4: r ≥ 6

Step-by-step explanation:

5(6+3r) + 7 ≥ 127

30 + 15r + 7 ≥ 127

37 + 15r ≥ 127

15r ≥ 90

r ≥ 6

5 0
3 years ago
Disregarding wind resistance the distance a body falls from rest varies directly as th squares of the time it falls if a skydive
Firdavs [7]

Answer:

The skydiver will fall 1600 ft in 10 seconds.

Step-by-step explanation:

<u>Distance a body falls from rest varies directly as the squares of the time it falls </u>

Let distance = s    

      time = t

Therefore , s = k \times t^{2}

Given, the body falls 64 ft in 2 seconds.

Substituting in above equation,

64 = k \times (2)^{2}

64 = k \times (4)

 k  = \frac{64}{4}

 k = 16 ft/s^{2}

We have to find how much he will fall in 10 seconds.

s = k \times t^{2}

s = 16 \times 10^{2}

s = 16 \times 100

s = 1600 ft

3 0
3 years ago
From a group of 6 candidates, a committee of 2 people is selected. In how many different ways can the committee be selected? I k
kolezko [41]
This is a combination problem. 

6 nCr 2

\frac{6!}{2! * (6-2)!} =  \frac{720}{48}=15<span><span>

</span></span>
7 0
3 years ago
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What is the length of a rectangle with an area of 48 yd squared, and a width of 3 yd
Leona [35]
The length of the rectangle is 16.
7 0
3 years ago
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HEEEEELP!!!!!!!!!!!!!11 I WILL MARK BRAINLIEST kx-3y=4 4x-5y=7 k is constant and x and y are variables, for what value of k will
Studentka2010 [4]

Answer:

<h2>               A.  ¹²/₅</h2>

Step-by-step explanation:

There is no solution for system of equations:  a_1x+b_1y=c_1\\a_2y+b_2y=c_2

if:     a_1=a_2\quad and\quad b_1=b_2\quad and\quad \bold{c_1\ne c_2}

so first, we we need to transform the equations to the form where the coefficients at y will be the same:

kx-3y=4\\ 4x-5y=7\\\\ (kx-3y)\cdot5=4\cdot5\\ (4x-5y)\cdot3=7\cdot3\\\\ 5kx-15y=20\\ 12x-15y=21

Now we have  b₁=b₂ and c₁≠c₂ so the system has no solution if a₁=a₂

5k = 12

÷5     ÷5

k = ¹²/₅

7 0
3 years ago
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