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2 years ago

PLEASE HELP NOW!!!!!!!!!

1 answer:

4 0

Answer: In the unlikely event that the owner is really, truly, okay with this, you will still have the reputation as a thief, someone who is unable to do anything original and has to steal in order to pretend to create something.

That reputation will follow you. And in the equally unlikely event, you should get fame, that reputation will ruin everything you gained and no one will ever trust that anything you write is actually yours.

Step-by-step explanation: Hope it's Helpful

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Pls just answer number 19 I will mark brainliest

bonufazy [111]

2 feet 7 inches.

5 feet - 2 feet is 3 feet
3 inches - 8 inches is - 5 inches.

just take the 5 inches from 3 feet to get 2 feet 7 inches.

7 0

3 years ago

Mrs. McCarthy bought 1.5 pounds of chicken from Smiths. She paid a total of $6.75 for the chicken. What was the price per pound?

REY [17]

$ 6.75/ 1.5 lbs

$4.50 per lb

4 0

3 years ago

Which domain restrictions apply to the rational expression?

andre [41]

Both expression have the same denominator: 9x²-1. Thus it must not be 0.

9x²-1=(3x-1)(3x+1)=0, resulting x=+-1/3.

Restrictions: x in R\{-1/3, 1/3}

Adding those expressions:

E=(-x-2)/(9x²-1 ) + (-5x+4)/(9x²-1)=

(-x-2-5x+4)/(9x²-1)=(-6x+2)/(9x²-1)=

(-2)(3x-1)/(9x²-1)=-2/(3x+1)

E=-2/(3x+1)

4 0

3 years ago

If sin x = 0.5 what is the value of cos X?<br>round the value to the nearest thousandth

Mariana [72]

Cos(arcsin(0.5)) = 0.866

8 0

3 years ago

Read 2 more answers

Which of the following functions gives the length of the base edge, a(v), of a right square pyramid that is 8 inches tall as a f

Reil [10]

Answer:

$\large\boxed{a(V)=\sqrt{\dfrac{3V}{8}}}$

Step-by-step explanation:

The formula of a volume of a square pyramid:

$V=\dfrac{1}{3}a^2h$

a - base edge

h - height of a pyramid

We have H = 8in.

Substitute and solve for a:

$\dfrac{1}{3}a^2(8)=V\\\\\dfrac{8}{3}a^2=V\qquad\text{multiply both sides by}\ \dfrac{3}{8}\\\\\dfrac{3\!\!\!\!\diagup^1}{8\!\!\!\!\diagup_1}\cdot\dfrac{8\!\!\!\!\diagup^1}{3\!\!\!\!\diagup_1}a^2=\dfrac{3}{8}V\\\\a^2=\dfrac{3V}{8}\Rightarrow a=\sqrt{\dfrac{3V}{8}}$

3 0

3 years ago