There asking for the equation, and the possible answers are
y = 2x + 6
y = −one halfx + 3
y = −one halfx + 6
y = 2x + 3
Answer:
4.5
Step-by-step explanation:
First we need to turn the ratio of 1 : 3 into a fraction
1:3 = 1/3
Next we need to square that fraction
1 x 1 = 1
3 x 3 = 9
Then we turn those numbers into a fraction
1/9
We turn the .5 into a fraction
.5/x
And cross multiply both fraction by each other
1/9 x .5/x
1 x X = X
9 x .5 = 4.5
So
4.5 = X
49*4=196+1=197/4
<span>8*3=24+3=27/8 </span>
<span>then make the denominator the same</span>
<span>multiply 197*2 and 4*2 = 394/8 </span>
<span>then 394/8 +27/8 =421/8 </span>
<span>u can either leave it here or in decimal form which would be 52.625 or in mixed numbers-52 5/8</span>
Data:
r (radius) = 3.5 in
h (height) = 8 in
Adopt:

V (volume) = ?
Ink cost per cubic inch = $0.05/in³
Total cost: ?
<span>Calculate the volume of the paint bucket (its formed being cylindrical), we have:
</span>


<span>What was the total cost of the paint?
</span>price($)___measure(in³)
0.05 ---------- 1
y -------------- 307.72
It is made the rule of three: (<span>directly proportional)
</span>

multiply cross


Answer:
<span>
the total cost of the paint is $15</span>
Answer:
(a) ¬(p→¬q)
(b) ¬p→q
(c) ¬((p→q)→¬(q→p))
Step-by-step explanation
taking into account the truth table for the conditional connective:
<u>p | q | p→q </u>
T | T | T
T | F | F
F | T | T
F | F | T
(a) and (b) can be seen from truth tables:
for (a) <u>p∧q</u>:
<u>p | q | ¬q | p→¬q | ¬(p→¬q) | p∧q</u>
T | T | F | F | T | T
T | F | T | T | F | F
F | T | F | T | F | F
F | F | T | T | F | F
As they have the same truth table, they are equivalent.
In a similar manner, for (b) p∨q:
<u>p | q | ¬p | ¬p→q | p∨q</u>
T | T | F | T | T
T | F | F | T | T
F | T | T | T | T
F | F | T | F | F
again, the truth tables are the same.
For (c)p↔q, we have to remember that p ↔ q can be written as (p→q)∧(q→p). By replacing p with (p→q) and q with (q→p) in the answer for part (a) we can change the ∧ connector to an equivalent using ¬ and →. Doing this we get ¬((p→q)→¬(q→p))